let n be Element of NAT ; for A being non empty closed_interval Subset of REAL holds integral ((#Z n),A) = ((1 / (n + 1)) * ((upper_bound A) |^ (n + 1))) - ((1 / (n + 1)) * ((lower_bound A) |^ (n + 1)))
let A be non empty closed_interval Subset of REAL; integral ((#Z n),A) = ((1 / (n + 1)) * ((upper_bound A) |^ (n + 1))) - ((1 / (n + 1)) * ((lower_bound A) |^ (n + 1)))
A1:
dom (#Z n) = [#] REAL
by FUNCT_2:def 1;
A2:
for x being Element of REAL st x in dom (((1 / (n + 1)) (#) (#Z (n + 1))) `| REAL) holds
(((1 / (n + 1)) (#) (#Z (n + 1))) `| REAL) . x = (#Z n) . x
( dom (#Z (n + 1)) = [#] REAL & ( for x being Real st x in REAL holds
#Z (n + 1) is_differentiable_in x ) )
by FUNCT_2:def 1, TAYLOR_1:2;
then
( [#] REAL = dom ((1 / (n + 1)) (#) (#Z (n + 1))) & #Z (n + 1) is_differentiable_on REAL )
by FDIFF_1:9, FUNCT_2:def 1;
then
(1 / (n + 1)) (#) (#Z (n + 1)) is_differentiable_on REAL
by FDIFF_1:20;
then
dom (((1 / (n + 1)) (#) (#Z (n + 1))) `| REAL) = dom (#Z n)
by A1, FDIFF_1:def 7;
then A3:
((1 / (n + 1)) (#) (#Z (n + 1))) `| REAL = #Z n
by A2, PARTFUN1:5;
A4: (#Z (n + 1)) . (upper_bound A) =
(upper_bound A) #Z (n + 1)
by TAYLOR_1:def 1
.=
(upper_bound A) |^ (n + 1)
by PREPOWER:36
;
for x being Real st x in REAL holds
#Z n is_differentiable_in x
by TAYLOR_1:2;
then
#Z n is_differentiable_on REAL
by A1, FDIFF_1:9;
then A5:
(#Z n) | REAL is continuous
by FDIFF_1:25;
then
(#Z n) | A is continuous
by FCONT_1:16;
then A6:
#Z n is_integrable_on A
by A1, INTEGRA5:11;
A7: (#Z (n + 1)) . (lower_bound A) =
(lower_bound A) #Z (n + 1)
by TAYLOR_1:def 1
.=
(lower_bound A) |^ (n + 1)
by PREPOWER:36
;
(#Z n) | A is bounded
by A1, A5, FCONT_1:16, INTEGRA5:10;
then integral ((#Z n),A) =
(((1 / (n + 1)) (#) (#Z (n + 1))) . (upper_bound A)) - (((1 / (n + 1)) (#) (#Z (n + 1))) . (lower_bound A))
by A6, A3, Th18, INTEGRA5:13
.=
((1 / (n + 1)) * ((#Z (n + 1)) . (upper_bound A))) - (((1 / (n + 1)) (#) (#Z (n + 1))) . (lower_bound A))
by VALUED_1:6
.=
((1 / (n + 1)) * ((#Z (n + 1)) . (upper_bound A))) - ((1 / (n + 1)) * ((#Z (n + 1)) . (lower_bound A)))
by VALUED_1:6
.=
((1 / (n + 1)) * ((upper_bound A) |^ (n + 1))) - ((1 / (n + 1)) * ((lower_bound A) |^ (n + 1)))
by A4, A7
;
hence
integral ((#Z n),A) = ((1 / (n + 1)) * ((upper_bound A) |^ (n + 1))) - ((1 / (n + 1)) * ((lower_bound A) |^ (n + 1)))
; verum