let A be non empty closed_interval Subset of REAL; for r being Real holds integral ((r (#) sinh),A) = (r * (cosh . (upper_bound A))) - (r * (cosh . (lower_bound A)))
let r be Real; integral ((r (#) sinh),A) = (r * (cosh . (upper_bound A))) - (r * (cosh . (lower_bound A)))
A1:
[#] REAL is open Subset of REAL
;
( sinh | A is continuous & sinh | A is bounded )
by Lm9, Lm14, INTEGRA5:10;
hence
integral ((r (#) sinh),A) = (r * (cosh . (upper_bound A))) - (r * (cosh . (lower_bound A)))
by A1, Lm9, Th31, Th68, INTEGRA5:11, SIN_COS2:35; verum