let a, b be Real; (cos . a) - (cos . b) = integral (sin,a,b)
A1:
min (a,b) <= a
by XXREAL_0:17;
max (a,b) in REAL
by XREAL_0:def 1;
then A2:
max (a,b) in dom ((- 1) (#) cos)
by SIN_COS:24, VALUED_1:def 5;
min (a,b) in REAL
by XREAL_0:def 1;
then A3:
min (a,b) in dom ((- 1) (#) cos)
by SIN_COS:24, VALUED_1:def 5;
A4:
( a <= max (a,b) & [.(min (a,b)),(max (a,b)).] c= REAL )
by XXREAL_0:25;
( sin | REAL is continuous & REAL c= dom sin )
by FDIFF_1:25, FUNCT_2:def 1, SIN_COS:68;
then
((- 1) (#) cos) . (max (a,b)) = (integral (sin,(min (a,b)),(max (a,b)))) + (((- 1) (#) cos) . (min (a,b)))
by A1, A4, Th20, Th25, XXREAL_0:2;
then
(- 1) * (cos . (max (a,b))) = (integral (sin,(min (a,b)),(max (a,b)))) + (((- 1) (#) cos) . (min (a,b)))
by A2, VALUED_1:def 5;
then
(- 1) * (cos . (max (a,b))) = (integral (sin,(min (a,b)),(max (a,b)))) + ((- 1) * (cos . (min (a,b))))
by A3, VALUED_1:def 5;
then A5:
(cos . (min (a,b))) - (cos . (max (a,b))) = integral (sin,(min (a,b)),(max (a,b)))
;
now ( min (a,b) = b implies (cos . a) - (cos . b) = integral (sin,a,b) )assume A8:
min (
a,
b)
= b
;
(cos . a) - (cos . b) = integral (sin,a,b)then A9:
max (
a,
b)
= a
by XXREAL_0:36;
(
b < a implies
(cos . a) - (cos . b) = integral (
sin,
a,
b) )
proof
assume A10:
b < a
;
(cos . a) - (cos . b) = integral (sin,a,b)
then
integral (
sin,
a,
b)
= - (integral (sin,['b,a']))
by INTEGRA5:def 4;
then
integral (
sin,
a,
b)
= - (integral (sin,b,a))
by A10, INTEGRA5:def 4;
hence
(cos . a) - (cos . b) = integral (
sin,
a,
b)
by A5, A8, A9;
verum
end; hence
(cos . a) - (cos . b) = integral (
sin,
a,
b)
by A1, A6, A8, XXREAL_0:1;
verum end;
hence
(cos . a) - (cos . b) = integral (sin,a,b)
by A6, XXREAL_0:15; verum