let a, b be Real; (sin . b) - (sin . a) = integral (cos,a,b)
A1:
min (a,b) <= a
by XXREAL_0:17;
A2:
( REAL = dom cos & [.(min (a,b)),(max (a,b)).] c= REAL )
by FUNCT_2:def 1;
( cos | REAL is continuous & a <= max (a,b) )
by FDIFF_1:25, SIN_COS:67, XXREAL_0:25;
then A3:
sin . (max (a,b)) = (integral (cos,(min (a,b)),(max (a,b)))) + (sin . (min (a,b)))
by A1, A2, Th20, Th23, XXREAL_0:2;
now ( min (a,b) = b implies (sin . b) - (sin . a) = integral (cos,a,b) )assume A6:
min (
a,
b)
= b
;
(sin . b) - (sin . a) = integral (cos,a,b)then A7:
max (
a,
b)
= a
by XXREAL_0:36;
now ( b < a implies (sin . b) - (sin . a) = integral (cos,a,b) )assume
b < a
;
(sin . b) - (sin . a) = integral (cos,a,b)then
integral (
cos,
a,
b)
= - (integral (cos,['b,a']))
by INTEGRA5:def 4;
then
sin . a = (- (integral (cos,a,b))) + (sin . b)
by A1, A3, A6, A7, INTEGRA5:def 4;
hence
(sin . b) - (sin . a) = integral (
cos,
a,
b)
;
verum end; hence
(sin . b) - (sin . a) = integral (
cos,
a,
b)
by A1, A4, A6, XXREAL_0:1;
verum end;
hence
(sin . b) - (sin . a) = integral (cos,a,b)
by A4, XXREAL_0:15; verum