let A be non empty closed_interval Subset of REAL; for f being Function of A,REAL st f | A is bounded & ( for x being Real st x in A holds
f . x >= 0 ) holds
integral f >= 0
let f be Function of A,REAL; ( f | A is bounded & ( for x being Real st x in A holds
f . x >= 0 ) implies integral f >= 0 )
assume that
A1:
f | A is bounded
and
A2:
for x being Real st x in A holds
f . x >= 0
; integral f >= 0
A3:
for a being Real st a in rng (upper_sum_set f) holds
a >= 0
proof
let a be
Real;
( a in rng (upper_sum_set f) implies a >= 0 )
assume
a in rng (upper_sum_set f)
;
a >= 0
then consider D being
Element of
divs A such that A4:
(
D in dom (upper_sum_set f) &
a = (upper_sum_set f) . D )
by PARTFUN1:3;
reconsider D =
D as
Division of
A by INTEGRA1:def 3;
A5:
for
i being
Nat st
i in dom (upper_volume (f,D)) holds
0 <= (upper_volume (f,D)) . i
proof
let i be
Nat;
( i in dom (upper_volume (f,D)) implies 0 <= (upper_volume (f,D)) . i )
set r =
(upper_volume (f,D)) . i;
assume A6:
i in dom (upper_volume (f,D))
;
0 <= (upper_volume (f,D)) . i
len D = len (upper_volume (f,D))
by INTEGRA1:def 6;
then A7:
i in dom D
by A6, FINSEQ_3:29;
A8:
upper_bound (rng (f | (divset (D,i)))) >= 0
proof
rng f is
bounded_above
by A1, INTEGRA1:13;
then A9:
rng (f | (divset (D,i))) is
bounded_above
by RELAT_1:70, XXREAL_2:43;
(
dom (f | (divset (D,i))) = (dom f) /\ (divset (D,i)) &
dom f = A )
by FUNCT_2:def 1, RELAT_1:61;
then
dom (f | (divset (D,i))) is non
empty Subset of
REAL
by A7, INTEGRA1:8, XBOOLE_1:28;
then consider x being
Element of
REAL such that A10:
x in dom (f | (divset (D,i)))
by SUBSET_1:4;
f . x >= 0
by A2, A10;
then A11:
(f | (divset (D,i))) . x >= 0
by A10, FUNCT_1:47;
(f | (divset (D,i))) . x in rng (f | (divset (D,i)))
by A10, FUNCT_1:def 3;
hence
upper_bound (rng (f | (divset (D,i)))) >= 0
by A9, A11, SEQ_4:def 1;
verum
end;
A12:
vol (divset (D,i)) >= 0
by INTEGRA1:9;
(upper_volume (f,D)) . i = (upper_bound (rng (f | (divset (D,i))))) * (vol (divset (D,i)))
by A7, INTEGRA1:def 6;
hence
0 <= (upper_volume (f,D)) . i
by A12, A8;
verum
end;
a =
upper_sum (
f,
D)
by A4, INTEGRA1:def 10
.=
Sum (upper_volume (f,D))
by INTEGRA1:def 8
;
hence
a >= 0
by A5, RVSUM_1:84;
verum
end;
( upper_integral f = lower_bound (rng (upper_sum_set f)) & not rng (upper_sum_set f) is empty )
by INTEGRA1:def 14;
then
upper_integral f >= 0
by A3, SEQ_4:43;
hence
integral f >= 0
by INTEGRA1:def 17; verum