let p, q be R_eal; for f1, f2 being PartFunc of REAL,REAL st f1 is_differentiable_on ].p,q.[ & f2 is_differentiable_on ].p,q.[ & ( for x being Real st x in ].p,q.[ holds
diff (f1,x) = diff (f2,x) ) holds
( (f1 - f2) | ].p,q.[ is constant & ex r being Real st
for x being Real st x in ].p,q.[ holds
f1 . x = (f2 . x) + r )
let f1, f2 be PartFunc of REAL,REAL; ( f1 is_differentiable_on ].p,q.[ & f2 is_differentiable_on ].p,q.[ & ( for x being Real st x in ].p,q.[ holds
diff (f1,x) = diff (f2,x) ) implies ( (f1 - f2) | ].p,q.[ is constant & ex r being Real st
for x being Real st x in ].p,q.[ holds
f1 . x = (f2 . x) + r ) )
assume that
A1:
( f1 is_differentiable_on ].p,q.[ & f2 is_differentiable_on ].p,q.[ )
and
A2:
for x being Real st x in ].p,q.[ holds
diff (f1,x) = diff (f2,x)
; ( (f1 - f2) | ].p,q.[ is constant & ex r being Real st
for x being Real st x in ].p,q.[ holds
f1 . x = (f2 . x) + r )
].p,q.[ is open_interval
by MEASURE5:def 2;
then reconsider Z = ].p,q.[ as open Subset of REAL ;
].p,q.[ c= (dom f1) /\ (dom f2)
by A1, XBOOLE_1:19;
then A3:
].p,q.[ c= dom (f1 - f2)
by VALUED_1:12;
then A4:
f1 - f2 is_differentiable_on Z
by A1, FDIFF_1:19;
now for x being Real st x in ].p,q.[ holds
diff ((f1 - f2),x) = 0 let x be
Real;
( x in ].p,q.[ implies diff ((f1 - f2),x) = 0 )assume A5:
x in ].p,q.[
;
diff ((f1 - f2),x) = 0 then
diff (
(f1 - f2),
x)
= ((f1 - f2) `| Z) . x
by A4, FDIFF_1:def 7;
then
diff (
(f1 - f2),
x)
= (diff (f1,x)) - (diff (f2,x))
by A1, A3, A5, FDIFF_1:19;
then
diff (
(f1 - f2),
x)
= (diff (f1,x)) - (diff (f1,x))
by A2, A5;
hence
diff (
(f1 - f2),
x)
= 0
;
verum end;
then A6:
(f1 - f2) | Z is constant
by A1, A3, Th19, FDIFF_1:19;
hence
(f1 - f2) | ].p,q.[ is constant
; ex r being Real st
for x being Real st x in ].p,q.[ holds
f1 . x = (f2 . x) + r
consider r being Element of REAL such that
A7:
for x being Element of REAL st x in ].p,q.[ /\ (dom (f1 - f2)) holds
(f1 - f2) . x = r
by A6, PARTFUN2:57;
take
r
; for x being Real st x in ].p,q.[ holds
f1 . x = (f2 . x) + r
let x be Real; ( x in ].p,q.[ implies f1 . x = (f2 . x) + r )
assume A8:
x in ].p,q.[
; f1 . x = (f2 . x) + r
then
x in ].p,q.[ /\ (dom (f1 - f2))
by A3, XBOOLE_1:28;
then
r = (f1 - f2) . x
by A7;
then
r = (f1 . x) - (f2 . x)
by A3, A8, VALUED_1:13;
hence
f1 . x = (f2 . x) + r
; verum