let n be Element of NAT ; for a, b, c, d, r being Real
for f being PartFunc of REAL,(REAL n) st a <= b & f is_integrable_on ['a,b'] & f | ['a,b'] is bounded & ['a,b'] c= dom f & c in ['a,b'] & d in ['a,b'] holds
integral ((r (#) f),c,d) = r * (integral (f,c,d))
let a, b, c, d, r be Real; for f being PartFunc of REAL,(REAL n) st a <= b & f is_integrable_on ['a,b'] & f | ['a,b'] is bounded & ['a,b'] c= dom f & c in ['a,b'] & d in ['a,b'] holds
integral ((r (#) f),c,d) = r * (integral (f,c,d))
let f be PartFunc of REAL,(REAL n); ( a <= b & f is_integrable_on ['a,b'] & f | ['a,b'] is bounded & ['a,b'] c= dom f & c in ['a,b'] & d in ['a,b'] implies integral ((r (#) f),c,d) = r * (integral (f,c,d)) )
assume A1:
( a <= b & f is_integrable_on ['a,b'] & f | ['a,b'] is bounded & ['a,b'] c= dom f & c in ['a,b'] & d in ['a,b'] )
; integral ((r (#) f),c,d) = r * (integral (f,c,d))
A2:
now for i being Element of NAT st i in Seg n holds
integral (((proj (i,n)) * (r (#) f)),c,d) = r * (integral (((proj (i,n)) * f),c,d))let i be
Element of
NAT ;
( i in Seg n implies integral (((proj (i,n)) * (r (#) f)),c,d) = r * (integral (((proj (i,n)) * f),c,d)) )set P =
proj (
i,
n);
assume A3:
i in Seg n
;
integral (((proj (i,n)) * (r (#) f)),c,d) = r * (integral (((proj (i,n)) * f),c,d))then A4:
(proj (i,n)) * f is_integrable_on ['a,b']
by A1;
(proj (i,n)) * (f | ['a,b']) is
bounded
by A3, A1;
then A5:
((proj (i,n)) * f) | ['a,b'] is
bounded
by RELAT_1:83;
dom (proj (i,n)) = REAL n
by FUNCT_2:def 1;
then
rng f c= dom (proj (i,n))
;
then A6:
['a,b'] c= dom ((proj (i,n)) * f)
by A1, RELAT_1:27;
(proj (i,n)) * (r (#) f) = r (#) ((proj (i,n)) * f)
by INTEGR15:16;
hence
integral (
((proj (i,n)) * (r (#) f)),
c,
d)
= r * (integral (((proj (i,n)) * f),c,d))
by A4, A5, A6, A1, INTEGRA6:25;
verum end;
A7:
now for i being Nat st i in dom (integral ((r (#) f),c,d)) holds
(integral ((r (#) f),c,d)) . i = (r * (integral (f,c,d))) . ilet i be
Nat;
( i in dom (integral ((r (#) f),c,d)) implies (integral ((r (#) f),c,d)) . i = (r * (integral (f,c,d))) . i )assume
i in dom (integral ((r (#) f),c,d))
;
(integral ((r (#) f),c,d)) . i = (r * (integral (f,c,d))) . ithen A8:
i in Seg n
by INTEGR15:def 18;
set P =
proj (
i,
n);
thus (integral ((r (#) f),c,d)) . i =
integral (
((proj (i,n)) * (r (#) f)),
c,
d)
by A8, INTEGR15:def 18
.=
r * (integral (((proj (i,n)) * f),c,d))
by A8, A2
.=
r * ((integral (f,c,d)) . i)
by A8, INTEGR15:def 18
.=
(r * (integral (f,c,d))) . i
by RVSUM_1:44
;
verum end;
A9:
Seg n = dom (integral ((r (#) f),c,d))
by INTEGR15:def 18;
len (r * (integral (f,c,d))) = n
by CARD_1:def 7;
then
Seg n = dom (r * (integral (f,c,d)))
by FINSEQ_1:def 3;
hence
integral ((r (#) f),c,d) = r * (integral (f,c,d))
by A9, A7, FINSEQ_1:13; verum