let r be Real; for A being non empty closed_interval Subset of REAL
for f being PartFunc of REAL,COMPLEX st A c= dom f & f is_integrable_on A & f | A is bounded holds
( r (#) f is_integrable_on A & integral ((r (#) f),A) = r * (integral (f,A)) )
let A be non empty closed_interval Subset of REAL; for f being PartFunc of REAL,COMPLEX st A c= dom f & f is_integrable_on A & f | A is bounded holds
( r (#) f is_integrable_on A & integral ((r (#) f),A) = r * (integral (f,A)) )
let f be PartFunc of REAL,COMPLEX; ( A c= dom f & f is_integrable_on A & f | A is bounded implies ( r (#) f is_integrable_on A & integral ((r (#) f),A) = r * (integral (f,A)) ) )
assume that
A1:
A c= dom f
and
A2:
f is_integrable_on A
and
A3:
f | A is bounded
; ( r (#) f is_integrable_on A & integral ((r (#) f),A) = r * (integral (f,A)) )
A4:
( Re f is_integrable_on A & Im f is_integrable_on A )
by A2;
A5:
( integral ((r (#) (Re f)),A) = r * (integral ((Re f),A)) & integral ((r (#) (Im f)),A) = r * (integral ((Im f),A)) )
proof
(
Re (f | A) is
bounded &
Im (f | A) is
bounded )
by A3, Th11;
then A6:
(
(Re f) | A is
bounded &
(Im f) | A is
bounded )
by Lm4;
A7:
(
A c= dom (Re f) &
A c= dom (Im f) )
by A1, COMSEQ_3:def 3, COMSEQ_3:def 4;
hence
integral (
(r (#) (Re f)),
A)
= r * (integral ((Re f),A))
by A4, A6, INTEGRA6:9;
integral ((r (#) (Im f)),A) = r * (integral ((Im f),A))
thus
integral (
(r (#) (Im f)),
A)
= r * (integral ((Im f),A))
by A4, A6, A7, INTEGRA6:9;
verum
end;
A8:
( Re (integral ((r (#) f),A)) = r * (Re (integral (f,A))) & Im (integral ((r (#) f),A)) = r * (Im (integral (f,A))) )
proof
(
Re (integral ((r (#) f),A)) = integral (
(Re (r (#) f)),
A) &
r * (Re (integral (f,A))) = r * (integral ((Re f),A)) &
Im (integral ((r (#) f),A)) = integral (
(Im (r (#) f)),
A) &
r * (Im (integral (f,A))) = r * (integral ((Im f),A)) )
by COMPLEX1:12;
hence
(
Re (integral ((r (#) f),A)) = r * (Re (integral (f,A))) &
Im (integral ((r (#) f),A)) = r * (Im (integral (f,A))) )
by A5, MESFUN6C:2;
verum
end;
( Re (r (#) f) is_integrable_on A & Im (r (#) f) is_integrable_on A )
hence
r (#) f is_integrable_on A
; integral ((r (#) f),A) = r * (integral (f,A))
( Re (integral ((r (#) f),A)) = Re (r * (integral (f,A))) & Im (integral ((r (#) f),A)) = Im (r * (integral (f,A))) )
by A8, Th1;
hence
integral ((r (#) f),A) = r * (integral (f,A))
; verum