let A be non empty closed_interval Subset of REAL; for f, f1 being PartFunc of REAL,REAL
for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
f1 . x = 1 ) & f = arccot / (f1 + (#Z 2)) & Z c= ].(- 1),1.[ & Z c= dom ((#Z 2) * arccot) & Z = dom f & f | A is continuous holds
integral (f,A) = ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (upper_bound A)) - ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (lower_bound A))
let f, f1 be PartFunc of REAL,REAL; for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
f1 . x = 1 ) & f = arccot / (f1 + (#Z 2)) & Z c= ].(- 1),1.[ & Z c= dom ((#Z 2) * arccot) & Z = dom f & f | A is continuous holds
integral (f,A) = ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (upper_bound A)) - ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (lower_bound A))
let Z be open Subset of REAL; ( A c= Z & ( for x being Real st x in Z holds
f1 . x = 1 ) & f = arccot / (f1 + (#Z 2)) & Z c= ].(- 1),1.[ & Z c= dom ((#Z 2) * arccot) & Z = dom f & f | A is continuous implies integral (f,A) = ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (upper_bound A)) - ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (lower_bound A)) )
assume A1:
( A c= Z & ( for x being Real st x in Z holds
f1 . x = 1 ) & f = arccot / (f1 + (#Z 2)) & Z c= ].(- 1),1.[ & Z c= dom ((#Z 2) * arccot) & Z = dom f & f | A is continuous )
; integral (f,A) = ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (upper_bound A)) - ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
A3:
- ((1 / 2) (#) ((#Z 2) * arccot)) is_differentiable_on Z
by A1, Th44;
Z c= (dom arccot) /\ ((dom (f1 + (#Z 2))) \ ((f1 + (#Z 2)) " {0}))
by A1, RFUNCT_1:def 1;
then
Z c= (dom (f1 + (#Z 2))) \ ((f1 + (#Z 2)) " {0})
by XBOOLE_1:18;
then A4:
Z c= dom ((f1 + (#Z 2)) ^)
by RFUNCT_1:def 2;
dom ((f1 + (#Z 2)) ^) c= dom (f1 + (#Z 2))
by RFUNCT_1:1;
then A5:
Z c= dom (f1 + (#Z 2))
by A4;
A6:
for x being Real st x in Z holds
f . x = (arccot . x) / (1 + (x ^2))
A8:
for x being Element of REAL st x in dom ((- ((1 / 2) (#) ((#Z 2) * arccot))) `| Z) holds
((- ((1 / 2) (#) ((#Z 2) * arccot))) `| Z) . x = f . x
dom ((- ((1 / 2) (#) ((#Z 2) * arccot))) `| Z) = dom f
by A1, A3, FDIFF_1:def 7;
then
(- ((1 / 2) (#) ((#Z 2) * arccot))) `| Z = f
by A8, PARTFUN1:5;
hence
integral (f,A) = ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (upper_bound A)) - ((- ((1 / 2) (#) ((#Z 2) * arccot))) . (lower_bound A))
by A1, A2, Th44, INTEGRA5:13; verum