let A be non empty closed_interval Subset of REAL; for f, f1 being PartFunc of REAL,REAL
for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
( f1 . x = 1 & arctan . x > 0 ) ) & f = ((f1 + (#Z 2)) (#) arctan) ^ & Z c= ].(- 1),1.[ & Z c= dom (ln * arctan) & Z = dom f & f | A is continuous holds
integral (f,A) = ((ln * arctan) . (upper_bound A)) - ((ln * arctan) . (lower_bound A))
let f, f1 be PartFunc of REAL,REAL; for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
( f1 . x = 1 & arctan . x > 0 ) ) & f = ((f1 + (#Z 2)) (#) arctan) ^ & Z c= ].(- 1),1.[ & Z c= dom (ln * arctan) & Z = dom f & f | A is continuous holds
integral (f,A) = ((ln * arctan) . (upper_bound A)) - ((ln * arctan) . (lower_bound A))
let Z be open Subset of REAL; ( A c= Z & ( for x being Real st x in Z holds
( f1 . x = 1 & arctan . x > 0 ) ) & f = ((f1 + (#Z 2)) (#) arctan) ^ & Z c= ].(- 1),1.[ & Z c= dom (ln * arctan) & Z = dom f & f | A is continuous implies integral (f,A) = ((ln * arctan) . (upper_bound A)) - ((ln * arctan) . (lower_bound A)) )
assume A1:
( A c= Z & ( for x being Real st x in Z holds
( f1 . x = 1 & arctan . x > 0 ) ) & f = ((f1 + (#Z 2)) (#) arctan) ^ & Z c= ].(- 1),1.[ & Z c= dom (ln * arctan) & Z = dom f & f | A is continuous )
; integral (f,A) = ((ln * arctan) . (upper_bound A)) - ((ln * arctan) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
A3:
for x being Real st x in Z holds
arctan . x > 0
by A1;
then A4:
ln * arctan is_differentiable_on Z
by A1, SIN_COS9:89;
Z c= dom ((f1 + (#Z 2)) (#) arctan)
by A1, RFUNCT_1:1;
then
Z c= (dom (f1 + (#Z 2))) /\ (dom arctan)
by VALUED_1:def 4;
then A5:
Z c= dom (f1 + (#Z 2))
by XBOOLE_1:18;
A6:
for x being Real st x in Z holds
f . x = 1 / ((1 + (x ^2)) * (arctan . x))
A8:
for x being Element of REAL st x in dom ((ln * arctan) `| Z) holds
((ln * arctan) `| Z) . x = f . x
dom ((ln * arctan) `| Z) = dom f
by A1, A4, FDIFF_1:def 7;
then
(ln * arctan) `| Z = f
by A8, PARTFUN1:5;
hence
integral (f,A) = ((ln * arctan) . (upper_bound A)) - ((ln * arctan) . (lower_bound A))
by A1, A2, A4, INTEGRA5:13; verum