let A be non empty closed_interval Subset of REAL; for f, f1 being PartFunc of REAL,REAL
for Z being open Subset of REAL st A c= Z & Z c= ].(- 1),1.[ & ( for x being Real st x in Z holds
( arcsin . x > 0 & f1 . x = 1 ) ) & Z c= dom (ln * arcsin) & Z = dom f & f = (((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin) ^ holds
integral (f,A) = ((ln * arcsin) . (upper_bound A)) - ((ln * arcsin) . (lower_bound A))
let f, f1 be PartFunc of REAL,REAL; for Z being open Subset of REAL st A c= Z & Z c= ].(- 1),1.[ & ( for x being Real st x in Z holds
( arcsin . x > 0 & f1 . x = 1 ) ) & Z c= dom (ln * arcsin) & Z = dom f & f = (((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin) ^ holds
integral (f,A) = ((ln * arcsin) . (upper_bound A)) - ((ln * arcsin) . (lower_bound A))
let Z be open Subset of REAL; ( A c= Z & Z c= ].(- 1),1.[ & ( for x being Real st x in Z holds
( arcsin . x > 0 & f1 . x = 1 ) ) & Z c= dom (ln * arcsin) & Z = dom f & f = (((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin) ^ implies integral (f,A) = ((ln * arcsin) . (upper_bound A)) - ((ln * arcsin) . (lower_bound A)) )
assume A1:
( A c= Z & Z c= ].(- 1),1.[ & ( for x being Real st x in Z holds
( arcsin . x > 0 & f1 . x = 1 ) ) & Z c= dom (ln * arcsin) & Z = dom f & f = (((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin) ^ )
; integral (f,A) = ((ln * arcsin) . (upper_bound A)) - ((ln * arcsin) . (lower_bound A))
set g = ((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin;
A2:
Z c= dom (((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin)
by A1, RFUNCT_1:1;
dom (((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin) = (dom ((#R (1 / 2)) * (f1 - (#Z 2)))) /\ (dom arcsin)
by VALUED_1:def 4;
then A3:
( Z c= dom ((#R (1 / 2)) * (f1 - (#Z 2))) & Z c= dom arcsin )
by A2, XBOOLE_1:18;
A4:
arcsin is_differentiable_on Z
by A1, FDIFF_1:26, SIN_COS6:83;
set f2 = #Z 2;
for x being Real st x in Z holds
(f1 - (#Z 2)) . x > 0
then
for x being Real st x in Z holds
( f1 . x = 1 & (f1 - (#Z 2)) . x > 0 )
by A1;
then
(#R (1 / 2)) * (f1 - (#Z 2)) is_differentiable_on Z
by A3, FDIFF_7:22;
then A7:
((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin is_differentiable_on Z
by A2, A4, FDIFF_1:21;
for x being Real st x in Z holds
(((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin) . x <> 0
by A1, RFUNCT_1:3;
then
f is_differentiable_on Z
by A1, A7, FDIFF_2:22;
then
f | Z is continuous
by FDIFF_1:25;
then
f | A is continuous
by A1, FCONT_1:16;
then A8:
( f is_integrable_on A & f | A is bounded )
by A1, INTEGRA5:10, INTEGRA5:11;
A9:
for x being Real st x in Z holds
arcsin . x > 0
by A1;
then A10:
ln * arcsin is_differentiable_on Z
by A1, FDIFF_7:8;
A11:
for x being Real st x in Z holds
f . x = 1 / ((sqrt (1 - (x ^2))) * (arcsin . x))
proof
let x be
Real;
( x in Z implies f . x = 1 / ((sqrt (1 - (x ^2))) * (arcsin . x)) )
assume A12:
x in Z
;
f . x = 1 / ((sqrt (1 - (x ^2))) * (arcsin . x))
then A13:
(
x in dom (f1 - (#Z 2)) &
(f1 - (#Z 2)) . x in dom (#R (1 / 2)) )
by A3, FUNCT_1:11;
then A14:
(f1 - (#Z 2)) . x in right_open_halfline 0
by TAYLOR_1:def 4;
(
- 1
< x &
x < 1 )
by A1, A12, XXREAL_1:4;
then
(
0 < 1
+ x &
0 < 1
- x )
by XREAL_1:50, XREAL_1:148;
then A15:
0 < (1 + x) * (1 - x)
by XREAL_1:129;
((((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin) ^) . x =
1
/ ((((#R (1 / 2)) * (f1 - (#Z 2))) (#) arcsin) . x)
by A1, A12, RFUNCT_1:def 2
.=
1
/ ((((#R (1 / 2)) * (f1 - (#Z 2))) . x) * (arcsin . x))
by VALUED_1:5
.=
1
/ (((#R (1 / 2)) . ((f1 - (#Z 2)) . x)) * (arcsin . x))
by A3, A12, FUNCT_1:12
.=
1
/ ((((f1 - (#Z 2)) . x) #R (1 / 2)) * (arcsin . x))
by A14, TAYLOR_1:def 4
.=
1
/ ((((f1 . x) - ((#Z 2) . x)) #R (1 / 2)) * (arcsin . x))
by A13, VALUED_1:13
.=
1
/ ((((f1 . x) - (x #Z 2)) #R (1 / 2)) * (arcsin . x))
by TAYLOR_1:def 1
.=
1
/ ((((f1 . x) - (x ^2)) #R (1 / 2)) * (arcsin . x))
by FDIFF_7:1
.=
1
/ (((1 - (x ^2)) #R (1 / 2)) * (arcsin . x))
by A1, A12
.=
1
/ ((sqrt (1 - (x ^2))) * (arcsin . x))
by A15, FDIFF_7:2
;
hence
f . x = 1
/ ((sqrt (1 - (x ^2))) * (arcsin . x))
by A1;
verum
end;
A16:
for x being Element of REAL st x in dom ((ln * arcsin) `| Z) holds
((ln * arcsin) `| Z) . x = f . x
dom ((ln * arcsin) `| Z) = dom f
by A1, A10, FDIFF_1:def 7;
then
(ln * arcsin) `| Z = f
by A16, PARTFUN1:5;
hence
integral (f,A) = ((ln * arcsin) . (upper_bound A)) - ((ln * arcsin) . (lower_bound A))
by A1, A8, A10, INTEGRA5:13; verum