let n be Nat; for p being Prime
for fp being FinSequence of INT st len fp = n + 1 & p > 2 & not p divides fp . (n + 1) holds
for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= n
let p be Prime; for fp being FinSequence of INT st len fp = n + 1 & p > 2 & not p divides fp . (n + 1) holds
for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= n
defpred S1[ Nat] means for fp being FinSequence of INT st len fp = $1 + 1 & p > 2 & not p divides fp . ($1 + 1) holds
for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= $1;
A1:
for n being Nat st S1[n] holds
S1[n + 1]
proof
let n be
Nat;
( S1[n] implies S1[n + 1] )
assume A2:
S1[
n]
;
S1[n + 1]
let fp be
FinSequence of
INT ;
( len fp = (n + 1) + 1 & p > 2 & not p divides fp . ((n + 1) + 1) implies for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= n + 1 )
assume that A3:
len fp = (n + 1) + 1
and A4:
p > 2
and A5:
not
p divides fp . ((n + 1) + 1)
;
for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= n + 1
per cases
( for x being Integer holds ((Poly-INT fp) . x) mod p <> 0 or ex a being Integer st ((Poly-INT fp) . a) mod p = 0 )
;
suppose
ex
a being
Integer st
((Poly-INT fp) . a) mod p = 0
;
for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= n + 1then consider a being
Integer such that A9:
((Poly-INT fp) . a) mod p = 0
;
assume
ex
f being
FinSequence of
INT st
( ( for
d being
Nat st
d in dom f holds
((Poly-INT fp) . (f . d)) mod p = 0 ) & ( for
d,
e being
Nat st
d in dom f &
e in dom f &
d <> e holds
not
f . d,
f . e are_congruent_mod p ) &
len f > n + 1 )
;
contradictionthen consider f being
FinSequence of
INT such that A10:
for
d being
Nat st
d in dom f holds
((Poly-INT fp) . (f . d)) mod p = 0
and A11:
for
d,
e being
Nat st
d in dom f &
e in dom f &
d <> e holds
not
f . d,
f . e are_congruent_mod p
and A12:
len f > n + 1
;
consider fk being
FinSequence of
INT ,
r being
Integer such that A13:
len fk = n + 1
and A14:
for
x being
Element of
INT holds
(Poly-INT fp) . x = ((x - a) * ((Poly-INT fk) . x)) + r
and A15:
fp . (n + 2) = fk . (n + 1)
by A3, Th6;
a is
Element of
INT
by INT_1:def 2;
then A16:
((Poly-INT fp) . a) mod p =
(((a - a) * ((Poly-INT fk) . a)) + r) mod p
by A14
.=
r mod p
;
A17:
for
d being
Element of
NAT st
d in dom f holds
p divides ((f . d) - a) * ((Poly-INT fk) . (f . d))
per cases
( for d being Nat st d in dom f holds
not p divides (f . d) - a or ex d being Nat st
( d in dom f & p divides (f . d) - a ) )
;
suppose
ex
d being
Nat st
(
d in dom f &
p divides (f . d) - a )
;
contradictionthen consider d9 being
Element of
NAT such that A21:
d9 in dom f
and A22:
p divides (f . d9) - a
;
set f9 =
f - {(f . d9)};
A23:
for
d being
Nat st
d in dom (f - {(f . d9)}) holds
not
p divides ((f - {(f . d9)}) . d) - a
proof
given k being
Nat such that A24:
k in dom (f - {(f . d9)})
and A25:
p divides ((f - {(f . d9)}) . k) - a
;
contradiction
(f - {(f . d9)}) . k in rng (f - {(f . d9)})
by A24, FUNCT_1:3;
then A26:
(f - {(f . d9)}) . k in (rng f) \ {(f . d9)}
by FINSEQ_3:65;
then
(f - {(f . d9)}) . k in rng f
by XBOOLE_0:def 5;
then consider w being
object such that A27:
w in dom f
and A28:
f . w = (f - {(f . d9)}) . k
by FUNCT_1:def 3;
reconsider w =
w as
Element of
NAT by A27;
p divides ((f . w) - a) - ((f . d9) - a)
by A22, A25, A28, Th1;
then A29:
f . w,
f . d9 are_congruent_mod p
;
not
(f - {(f . d9)}) . k in {(f . d9)}
by A26, XBOOLE_0:def 5;
then
w <> d9
by A28, TARSKI:def 1;
hence
contradiction
by A11, A21, A27, A29;
verum
end; A30:
for
d being
Nat st
d in dom (f - {(f . d9)}) holds
((Poly-INT fk) . ((f - {(f . d9)}) . d)) mod p = 0
A32:
f is
one-to-one
by A11, INT_1:11;
then A33:
f - {(f . d9)} is
one-to-one
by FINSEQ_3:87;
A34:
for
d,
e being
Nat st
d in dom (f - {(f . d9)}) &
e in dom (f - {(f . d9)}) &
d <> e holds
not
(f - {(f . d9)}) . d,
(f - {(f . d9)}) . e are_congruent_mod p
proof
let d,
e be
Nat;
( d in dom (f - {(f . d9)}) & e in dom (f - {(f . d9)}) & d <> e implies not (f - {(f . d9)}) . d,(f - {(f . d9)}) . e are_congruent_mod p )
assume that A35:
d in dom (f - {(f . d9)})
and A36:
e in dom (f - {(f . d9)})
and A37:
d <> e
;
not (f - {(f . d9)}) . d,(f - {(f . d9)}) . e are_congruent_mod p
(f - {(f . d9)}) . e in rng (f - {(f . d9)})
by A36, FUNCT_1:3;
then
(f - {(f . d9)}) . e in (rng f) \ {(f . d9)}
by FINSEQ_3:65;
then
(f - {(f . d9)}) . e in rng f
by XBOOLE_0:def 5;
then consider w2 being
object such that A38:
w2 in dom f
and A39:
(f - {(f . d9)}) . e = f . w2
by FUNCT_1:def 3;
(f - {(f . d9)}) . d in rng (f - {(f . d9)})
by A35, FUNCT_1:3;
then
(f - {(f . d9)}) . d in (rng f) \ {(f . d9)}
by FINSEQ_3:65;
then
(f - {(f . d9)}) . d in rng f
by XBOOLE_0:def 5;
then consider w1 being
object such that A40:
w1 in dom f
and A41:
(f - {(f . d9)}) . d = f . w1
by FUNCT_1:def 3;
reconsider w1 =
w1,
w2 =
w2 as
Element of
NAT by A40, A38;
w1 <> w2
by A33, A35, A36, A37, A41, A39;
hence
not
(f - {(f . d9)}) . d,
(f - {(f . d9)}) . e are_congruent_mod p
by A11, A40, A41, A38, A39;
verum
end;
f . d9 in rng f
by A21, FUNCT_1:3;
then
len (f - {(f . d9)}) = (len f) - 1
by A32, FINSEQ_3:90;
then
len (f - {(f . d9)}) > (n + 1) - 1
by A12, XREAL_1:9;
hence
contradiction
by A2, A4, A5, A13, A15, A30, A34;
verum end; end; end; end;
end;
A42:
S1[ 0 ]
proof
let fp be
FinSequence of
INT ;
( len fp = 0 + 1 & p > 2 & not p divides fp . (0 + 1) implies for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= 0 )
assume that A43:
len fp = 0 + 1
and
p > 2
and A44:
not
p divides fp . (0 + 1)
;
for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= 0
assume
ex
fr being
FinSequence of
INT st
( ( for
d being
Nat st
d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for
d,
e being
Nat st
d in dom fr &
e in dom fr &
d <> e holds
not
fr . d,
fr . e are_congruent_mod p ) &
len fr > 0 )
;
contradiction
then consider fr being
FinSequence of
INT such that A45:
for
d being
Nat st
d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0
and
for
d,
e being
Nat st
d in dom fr &
e in dom fr &
d <> e holds
not
fr . d,
fr . e are_congruent_mod p
and A46:
len fr > 0
;
fr <> {}
by A46;
then A47:
((Poly-INT fp) . (fr . 1)) mod p = 0
by A45, FINSEQ_5:6;
A48:
fr . 1
in INT
by INT_1:def 2;
(Poly-INT fp) . (fr . 1) =
(INT --> (fp . 1)) . (fr . 1)
by A43, Th3
.=
fp . 1
by A48, FUNCOP_1:7
;
hence
contradiction
by A44, A47, Lm1;
verum
end;
for n being Nat holds S1[n]
from NAT_1:sch 2(A42, A1);
hence
for fp being FinSequence of INT st len fp = n + 1 & p > 2 & not p divides fp . (n + 1) holds
for fr being FinSequence of INT st ( for d being Nat st d in dom fr holds
((Poly-INT fp) . (fr . d)) mod p = 0 ) & ( for d, e being Nat st d in dom fr & e in dom fr & d <> e holds
not fr . d,fr . e are_congruent_mod p ) holds
len fr <= n
; verum