let n be non zero Nat; for lk being Nat
for Key being Matrix of lk,6,NAT
for k being Nat holds IDEA_P_F (Key,n,(k + 1)) = (IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>
let lk be Nat; for Key being Matrix of lk,6,NAT
for k being Nat holds IDEA_P_F (Key,n,(k + 1)) = (IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>
let Key be Matrix of lk,6,NAT; for k being Nat holds IDEA_P_F (Key,n,(k + 1)) = (IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>
let k be Nat; IDEA_P_F (Key,n,(k + 1)) = (IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>
A1:
for i being Nat st 1 <= i & i <= len (IDEA_P_F (Key,n,(k + 1))) holds
(IDEA_P_F (Key,n,(k + 1))) . i = ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i
proof
dom <*(IDEA_P ((Line (Key,(k + 1))),n))*> = Seg 1
by FINSEQ_1:def 8;
then A2:
1
in dom <*(IDEA_P ((Line (Key,(k + 1))),n))*>
by FINSEQ_1:1;
let i be
Nat;
( 1 <= i & i <= len (IDEA_P_F (Key,n,(k + 1))) implies (IDEA_P_F (Key,n,(k + 1))) . i = ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i )
assume that A3:
1
<= i
and A4:
i <= len (IDEA_P_F (Key,n,(k + 1)))
;
(IDEA_P_F (Key,n,(k + 1))) . i = ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i
i in Seg (len (IDEA_P_F (Key,n,(k + 1))))
by A3, A4, FINSEQ_1:1;
then A5:
i in dom (IDEA_P_F (Key,n,(k + 1)))
by FINSEQ_1:def 3;
A6:
i <= k + 1
by A4, Def17;
now ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i = (IDEA_P_F (Key,n,(k + 1))) . iper cases
( i <> k + 1 or i = k + 1 )
;
suppose
i <> k + 1
;
((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i = (IDEA_P_F (Key,n,(k + 1))) . ithen
i <= k
by A6, NAT_1:8;
then
i in Seg k
by A3, FINSEQ_1:1;
then
i in Seg (len (IDEA_P_F (Key,n,k)))
by Def17;
then A7:
i in dom (IDEA_P_F (Key,n,k))
by FINSEQ_1:def 3;
hence ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i =
(IDEA_P_F (Key,n,k)) . i
by FINSEQ_1:def 7
.=
IDEA_P (
(Line (Key,i)),
n)
by A7, Def17
.=
(IDEA_P_F (Key,n,(k + 1))) . i
by A5, Def17
;
verum end; suppose A8:
i = k + 1
;
((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i = (IDEA_P_F (Key,n,(k + 1))) . ihence ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i =
((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . ((len (IDEA_P_F (Key,n,k))) + 1)
by Def17
.=
<*(IDEA_P ((Line (Key,(k + 1))),n))*> . 1
by A2, FINSEQ_1:def 7
.=
IDEA_P (
(Line (Key,(k + 1))),
n)
.=
(IDEA_P_F (Key,n,(k + 1))) . i
by A5, A8, Def17
;
verum end; end; end;
hence
(IDEA_P_F (Key,n,(k + 1))) . i = ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) . i
;
verum
end;
len ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>) =
(len (IDEA_P_F (Key,n,k))) + (len <*(IDEA_P ((Line (Key,(k + 1))),n))*>)
by FINSEQ_1:22
.=
k + (len <*(IDEA_P ((Line (Key,(k + 1))),n))*>)
by Def17
.=
k + 1
by FINSEQ_1:39
;
then
len (IDEA_P_F (Key,n,(k + 1))) = len ((IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>)
by Def17;
hence
IDEA_P_F (Key,n,(k + 1)) = (IDEA_P_F (Key,n,k)) ^ <*(IDEA_P ((Line (Key,(k + 1))),n))*>
by A1, FINSEQ_1:14; verum