set g = Polynomial-Function (L,(p + q));
now for x being Element of L holds (Polynomial-Function (L,(p + q))) . (- x) = (Polynomial-Function (L,(p + q))) . xlet x be
Element of
L;
(Polynomial-Function (L,(p + q))) . (- x) = (Polynomial-Function (L,(p + q))) . xthus (Polynomial-Function (L,(p + q))) . (- x) =
eval (
(p + q),
(- x))
by POLYNOM5:def 13
.=
(eval (p,(- x))) + (eval (q,(- x)))
by POLYNOM4:19
.=
(eval (p,x)) + (eval (q,(- x)))
by Th24
.=
(eval (p,x)) + (eval (q,x))
by Th24
.=
eval (
(p + q),
x)
by POLYNOM4:19
.=
(Polynomial-Function (L,(p + q))) . x
by POLYNOM5:def 13
;
verum end;
hence
p + q is even
by Def3; verum