let X, Y be set ; ( X misses union Y implies card (UNION (Y,{X})) = card Y )
assume A1:
X misses union Y
; card (UNION (Y,{X})) = card Y
deffunc H1( set ) -> set = $1 \/ X;
consider f being Function such that
A2:
( dom f = Y & ( for A being set st A in Y holds
f . A = H1(A) ) )
from FUNCT_1:sch 5();
A3:
rng f c= UNION (Y,{X})
UNION (Y,{X}) c= rng f
then A6:
UNION (Y,{X}) = rng f
by A3;
f is one-to-one
hence
card (UNION (Y,{X})) = card Y
by CARD_1:5, A2, A6, WELLORD2:def 4; verum