let i, n1, n2 be Nat; for n being Nat
for i1 being Element of n holds { p where p is b1 -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | n2)) } is diophantine Subset of (n -xtuples_of NAT)
defpred S1[ Nat] means for n being Nat st $1 + n1 <= n holds
for i1 being Element of n holds { p where p is b1 -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | $1)) } is diophantine Subset of (n -xtuples_of NAT);
A1:
S1[ 0 ]
A3:
for m being Nat st S1[m] holds
S1[m + 1]
proof
let m be
Nat;
( S1[m] implies S1[m + 1] )
assume A4:
S1[
m]
;
S1[m + 1]
let n be
Nat;
( (m + 1) + n1 <= n implies for i1 being Element of n holds { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) } is diophantine Subset of (n -xtuples_of NAT) )
assume A5:
(m + 1) + n1 <= n
;
for i1 being Element of n holds { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) } is diophantine Subset of (n -xtuples_of NAT)
set m1 =
m + 1;
set X =
n + 1;
let i1 be
Element of
n;
{ p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) } is diophantine Subset of (n -xtuples_of NAT)
m < m + 1
by NAT_1:13;
then
n1 + m < n1 + (m + 1)
by XREAL_1:8;
then A6:
n1 + m < n
by A5, XXREAL_0:2;
then
n1 + m in Segm n
by NAT_1:44;
then reconsider n1m =
n1 + m as
Element of
n ;
A7:
n < n + 1
by NAT_1:13;
then
n in Segm (n + 1)
by NAT_1:44;
then reconsider N =
n,
I1 =
i1,
N1M =
n1m as
Element of
n + 1
by HILB10_3:2;
defpred S2[
XFinSequence of
NAT ]
means $1
. N = Product (i + (($1 /^ n1) | m));
defpred S3[
XFinSequence of
NAT ]
means $1
. I1 = ((1 * ($1 . N1M)) + i) * ($1 . N);
n1 + m <= n + 1
by A6, NAT_1:13;
then A8:
{ p where p is n + 1 -element XFinSequence of NAT : S2[p] } is
diophantine Subset of
((n + 1) -xtuples_of NAT)
by A4;
A9:
{ p where p is n + 1 -element XFinSequence of NAT : S3[p] } is
diophantine Subset of
((n + 1) -xtuples_of NAT)
by Th25;
set PQ =
{ p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } ;
A10:
{ p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } is
diophantine Subset of
((n + 1) -xtuples_of NAT)
from HILB10_3:sch 3(A8, A9);
set PQr =
{ (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } } ;
set S =
{ p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) } ;
A11:
{ (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } } is
diophantine Subset of
(n -xtuples_of NAT)
by HILB10_3:5, A7, A10;
A12:
(
n1 <= n1 + (m + 1) &
n1 + (m + 1) <= n )
by A5, NAT_1:11;
then A13:
n -' n1 = n - n1
by XXREAL_0:2, XREAL_1:233;
A14:
m + 1
<= n - n1
by A5, XREAL_1:19;
m < m + 1
by NAT_1:13;
then A15:
(
Segm m c= Segm (m + 1) &
m in Segm (m + 1) )
by NAT_1:39, NAT_1:44;
A16:
{ p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) } c= { (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } }
proof
let y be
object ;
TARSKI:def 3 ( not y in { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) } or y in { (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } } )
assume
y in { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) }
;
y in { (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } }
then consider p being
n -element XFinSequence of
NAT such that A17:
(
y = p &
p . i1 = Product (i + ((p /^ n1) | (m + 1))) )
;
A18:
len p = n
by CARD_1:def 7;
then A19:
len (p /^ n1) >= m + 1
by A14, A13, AFINSQ_2:def 2;
then
len ((p /^ n1) | (m + 1)) = m + 1
by AFINSQ_1:54;
then A20:
(p /^ n1) | (m + 1) = (((p /^ n1) | (m + 1)) | m) ^ <%(((p /^ n1) | (m + 1)) . m)%>
by AFINSQ_1:56;
(
((p /^ n1) | (m + 1)) | m = (p /^ n1) | m &
((p /^ n1) | (m + 1)) . m = (p /^ n1) . m &
m in dom (p /^ n1) )
by A19, AFINSQ_1:53, RELAT_1:74, A15;
then
(p /^ n1) | (m + 1) = ((p /^ n1) | m) ^ <%(p . n1m)%>
by A20, AFINSQ_2:def 2;
then i + ((p /^ n1) | (m + 1)) =
(i + ((p /^ n1) | m)) ^ (i + <%(p . n1m)%>)
by Th8
.=
(i + ((p /^ n1) | m)) ^ <%(i + (p . n1m))%>
by Th9
;
then A21:
Product (i + ((p /^ n1) | (m + 1))) =
(Product (i + ((p /^ n1) | m))) * (Product <%(i + (p . n1m))%>)
by Th7
.=
(Product (i + ((p /^ n1) | m))) * (i + (p . n1m))
by Th5
;
reconsider P =
Product (i + ((p /^ n1) | m)) as
Element of
NAT by ORDINAL1:def 12;
reconsider pP =
p ^ <%P%> as
n + 1
-element XFinSequence of
NAT ;
A22:
len (p /^ n1) > m
by A19, NAT_1:13;
A23:
(pP /^ n1) | m =
((p /^ n1) ^ <%P%>) | m
by Th10, A18, A12, XXREAL_0:2
.=
(p /^ n1) | m
by AFINSQ_1:58, A22
;
A24:
pP | n = p
by A18, AFINSQ_1:57;
A25:
(
pP . I1 = p . i1 &
pP . N1M = p . n1m )
by A5, A24, HILB10_3:4;
(
S2[
pP] &
S3[
pP] )
by A23, A25, A21, A18, AFINSQ_1:36, A17;
then
pP in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) }
;
hence
y in { (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } }
by A17, A24;
verum
end;
{ (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } } c= { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) }
proof
let y be
object ;
TARSKI:def 3 ( not y in { (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } } or y in { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) } )
assume
y in { (p | n) where p is n + 1 -element XFinSequence of NAT : p in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } }
;
y in { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) }
then consider pP being
n + 1
-element XFinSequence of
NAT such that A26:
(
y = pP | n &
pP in { p where p is n + 1 -element XFinSequence of NAT : ( S2[p] & S3[p] ) } )
;
A27:
ex
q being
n + 1
-element XFinSequence of
NAT st
(
pP = q &
S2[
q] &
S3[
q] )
by A26;
A28:
len pP = n + 1
by CARD_1:def 7;
A29:
len (pP | n) = n
by CARD_1:def 7;
set p =
pP | n;
A30:
len ((pP | n) /^ n1) >= m + 1
by A14, A13, A29, AFINSQ_2:def 2;
then
len (((pP | n) /^ n1) | (m + 1)) = m + 1
by AFINSQ_1:54;
then A31:
((pP | n) /^ n1) | (m + 1) = ((((pP | n) /^ n1) | (m + 1)) | m) ^ <%((((pP | n) /^ n1) | (m + 1)) . m)%>
by AFINSQ_1:56;
(
(((pP | n) /^ n1) | (m + 1)) | m = ((pP | n) /^ n1) | m &
(((pP | n) /^ n1) | (m + 1)) . m = ((pP | n) /^ n1) . m &
m in dom ((pP | n) /^ n1) )
by A30, AFINSQ_1:53, RELAT_1:74, A15;
then
((pP | n) /^ n1) | (m + 1) = (((pP | n) /^ n1) | m) ^ <%((pP | n) . n1m)%>
by A31, AFINSQ_2:def 2;
then i + (((pP | n) /^ n1) | (m + 1)) =
(i + (((pP | n) /^ n1) | m)) ^ (i + <%((pP | n) . n1m)%>)
by Th8
.=
(i + (((pP | n) /^ n1) | m)) ^ <%(i + ((pP | n) . n1m))%>
by Th9
;
then A32:
Product (i + (((pP | n) /^ n1) | (m + 1))) =
(Product (i + (((pP | n) /^ n1) | m))) * (Product <%(i + ((pP | n) . n1m))%>)
by Th7
.=
(Product (i + (((pP | n) /^ n1) | m))) * (i + ((pP | n) . n1m))
by Th5
;
set P =
Product (i + (((pP | n) /^ n1) | m));
A33:
pP = (pP | n) ^ <%(pP . n)%>
by A28, AFINSQ_1:56;
A34:
len ((pP | n) /^ n1) > m
by A30, NAT_1:13;
A35:
(pP /^ n1) | m =
(((pP | n) /^ n1) ^ <%(pP . n)%>) | m
by A33, Th10, A29, A12, XXREAL_0:2
.=
((pP | n) /^ n1) | m
by AFINSQ_1:58, A34
;
(
pP . I1 = (pP | n) . i1 &
pP . N1M = (pP | n) . n1m )
by A5, HILB10_3:4;
hence
y in { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) }
by A26, A35, A32, A27;
verum
end;
hence
{ p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | (m + 1))) } is
diophantine Subset of
(n -xtuples_of NAT)
by A11, A16, XBOOLE_0:def 10;
verum
end;
A36:
for m being Nat holds S1[m]
from NAT_1:sch 2(A1, A3);
let n be Nat; for i1 being Element of n holds { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | n2)) } is diophantine Subset of (n -xtuples_of NAT)
let i1 be Element of n; { p where p is n -element XFinSequence of NAT : p . i1 = Product (i + ((p /^ n1) | n2)) } is diophantine Subset of (n -xtuples_of NAT)