let n, k, u be Nat; :: thesis: ( u > n |^ k & n >= k implies [\(((u + 1) |^ n) / (u |^ k))/] mod u = n choose k )
assume A1: ( u > n |^ k & n >= k ) ; :: thesis: [\(((u + 1) |^ n) / (u |^ k))/] mod u = n choose k
set I = (1,u) In_Power n;
set k1 = k + 1;
consider q being FinSequence such that
A2: (1,u) In_Power n = (((1,u) In_Power n) | (k + 1)) ^ q by FINSEQ_1:80;
rng ((1,u) In_Power n) c= NAT by VALUED_0:def 6;
then reconsider I1 = (1,u) In_Power n as FinSequence of NAT by FINSEQ_1:def 4;
I1 = (I1 | (k + 1)) ^ q by A2;
then reconsider q = q as FinSequence of NAT by FINSEQ_1:36;
A3: len I1 = n + 1 by NEWTON:def 4;
A4: len (I1 | (k + 1)) = k + 1 by A1, XREAL_1:7, A3, FINSEQ_1:59;
1 <= k + 1 by NAT_1:11;
then k + 1 in dom ((1,u) In_Power n) by A3, A1, XREAL_1:7, FINSEQ_3:25;
then A5: I1 | (k + 1) = (I1 | k) ^ <*(I1 . (k + 1))*> by FINSEQ_5:10;
A6: Sum I1 = (Sum (I1 | (k + 1))) + (Sum q) by A2, RVSUM_1:75
.= ((Sum (I1 | k)) + (I1 . (k + 1))) + (Sum q) by A5, RVSUM_1:74 ;
k <= n + 1 by A1, NAT_1:13;
then A7: I1 | k is k -element by A3, FINSEQ_1:59;
set kI = k |-> ((u |^ k) / n);
A8: for i being Nat st i in Seg k holds
(I1 | k) . i < (k |-> ((u |^ k) / n)) . i
proof
let i be Nat; :: thesis: ( i in Seg k implies (I1 | k) . i < (k |-> ((u |^ k) / n)) . i )
assume A9: i in Seg k ; :: thesis: (I1 | k) . i < (k |-> ((u |^ k) / n)) . i
A10: (k |-> ((u |^ k) / n)) . i = (u |^ k) / n by A9, FINSEQ_2:57;
A11: ( 1 <= i & i <= k ) by A9, FINSEQ_1:1;
then A12: (I1 | k) . i = I1 . i by FINSEQ_3:112;
reconsider i1 = i - 1 as Nat by A11;
set ni = n -' i1;
A13: ( i1 + 1 = i & i <= n ) by A11, A1, XXREAL_0:2;
then A14: ( i1 < n & i <= n + 1 ) by NAT_1:13;
then A15: i in dom I1 by A11, A3, FINSEQ_3:25;
n -' i1 = n - i1 by A14, XREAL_1:233;
then A16: I1 . i = ((n choose i1) * (1 |^ (n -' i1))) * (u |^ i1) by A15, NEWTON:def 4;
k > i1 by A13, A11, NAT_1:13;
hence (I1 | k) . i < (k |-> ((u |^ k) / n)) . i by Th14, A1, A10, A16, A12; :: thesis: verum
end;
then A17: for i being Nat st i in Seg k holds
(I1 | k) . i <= (k |-> ((u |^ k) / n)) . i ;
1 <= k + 1 by NAT_1:11;
then A18: k + 1 in dom I1 by A1, XREAL_1:7, A3, FINSEQ_3:25;
( n - k = n -' k & k = (k + 1) - 1 ) by A1, XREAL_1:233;
then A19: I1 . (k + 1) = ((n choose k) * (1 |^ (n -' k))) * (u |^ k) by A18, NEWTON:def 4;
defpred S1[ Nat, object ] means ( $2 in NAT & ( for i being Nat st i = $2 holds
q . $1 = ((u |^ k) * u) * i ) );
len ((1,u) In_Power n) = (k + 1) + (len q) by A2, A4, FINSEQ_1:22;
then A20: n = k + (len q) by A3;
A21: for j being Nat st j in Seg (len q) holds
ex x being object st S1[j,x]
proof
let j be Nat; :: thesis: ( j in Seg (len q) implies ex x being object st S1[j,x] )
assume A22: j in Seg (len q) ; :: thesis: ex x being object st S1[j,x]
A23: ( 1 <= j & j <= len q ) by FINSEQ_1:1, A22;
A24: ((k + 1) + j) - 1 = k + j ;
A25: n >= k + j by A23, A20, XREAL_1:7;
A26: n -' (k + j) = n - (k + j) by XREAL_1:233, A23, A20, XREAL_1:7;
( 1 <= (k + j) + 1 & (k + j) + 1 <= n + 1 ) by NAT_1:11, A25, XREAL_1:7;
then (k + 1) + j in dom I1 by FINSEQ_3:25, A3;
then A27: I1 . ((k + 1) + j) = ((n choose (k + j)) * (1 |^ (n -' (k + j)))) * (u |^ (k + j)) by A24, A26, NEWTON:def 4;
reconsider j1 = j - 1 as Nat by A23;
A28: u |^ (k + j) = (u |^ k) * (u |^ (j1 + 1)) by NEWTON:8
.= (u |^ k) * ((u |^ j1) * u) by NEWTON:6 ;
take U = ((n choose (k + j)) * (1 |^ (n -' (k + j)))) * (u |^ j1); :: thesis: S1[j,U]
thus S1[j,U] by A27, A28, A23, FINSEQ_1:65, A2, A4, ORDINAL1:def 12; :: thesis: verum
end;
consider Q being FinSequence such that
A29: dom Q = Seg (len q) and
A30: for j being Nat st j in Seg (len q) holds
S1[j,Q . j] from FINSEQ_1:sch 1(A21);
rng Q c= NAT
proof
let y be object ; :: according to TARSKI:def 3 :: thesis: ( not y in rng Q or y in NAT )
assume A31: y in rng Q ; :: thesis: y in NAT
ex x being object st
( x in dom Q & Q . x = y ) by FUNCT_1:def 3, A31;
hence y in NAT by A30, A29; :: thesis: verum
end;
then reconsider Q = Q as FinSequence of NAT by FINSEQ_1:def 4;
A32: ( len Q = len q & len (((u |^ k) * u) * Q) = len Q ) by CARD_1:def 7, A29, FINSEQ_1:def 3;
for i being Nat st 1 <= i & i <= len q holds
q . i = (((u |^ k) * u) * Q) . i
proof
let i be Nat; :: thesis: ( 1 <= i & i <= len q implies q . i = (((u |^ k) * u) * Q) . i )
assume ( 1 <= i & i <= len q ) ; :: thesis: q . i = (((u |^ k) * u) * Q) . i
then i in dom Q by A29;
then q . i = ((u |^ k) * u) * (Q . i) by A29, A30;
hence q . i = (((u |^ k) * u) * Q) . i by VALUED_1:6; :: thesis: verum
end;
then q = ((u |^ k) * u) * Q by A32, FINSEQ_1:14;
then A33: Sum q = ((u |^ k) * u) * (Sum Q) by RVSUM_1:87;
A34: [\((Sum I1) / (u |^ k))/] = (n choose k) + (u * (Sum Q))
proof
per cases ( k = 0 or k >= 1 ) by NAT_1:14;
suppose k = 0 ; :: thesis: [\((Sum I1) / (u |^ k))/] = (n choose k) + (u * (Sum Q))
then Sum (I1 | k) = 0 ;
then 1 * (Sum I1) = (u |^ k) * ((n choose k) + (u * (Sum Q))) by A33, A19, A6;
then (Sum I1) / (u |^ k) = ((n choose k) + (u * (Sum Q))) / 1 by A1, XCMPLX_1:94;
hence [\((Sum I1) / (u |^ k))/] = (n choose k) + (u * (Sum Q)) ; :: thesis: verum
end;
suppose A35: k >= 1 ; :: thesis: [\((Sum I1) / (u |^ k))/] = (n choose k) + (u * (Sum Q))
then A36: k in Seg k ;
then A37: (I1 | k) . k < (k |-> ((u |^ k) / n)) . k by A8;
A38: Sum (k |-> ((u |^ k) / n)) = k * ((u |^ k) / n) by RVSUM_1:80
.= (u |^ k) * (k / n) by XCMPLX_1:75 ;
Sum (I1 | k) < (u |^ k) * (k / n) by A37, A36, A7, A17, RVSUM_1:83, A38;
then A39: (Sum (I1 | k)) + ((I1 . (k + 1)) + (Sum q)) < ((u |^ k) * (k / n)) + ((I1 . (k + 1)) + (Sum q)) by XREAL_1:8;
((u |^ k) * (k / n)) + ((I1 . (k + 1)) + (Sum q)) = (u |^ k) * (((k / n) + (n choose k)) + (u * (Sum Q))) by A33, A19;
then A40: (Sum I1) / (u |^ k) < ((k / n) + (n choose k)) + (u * (Sum Q)) by A1, A39, A6, XREAL_1:83;
( k / n <= n / n & n / n = 1 ) by A35, XREAL_1:72, A1, XCMPLX_1:60;
then (k / n) + ((n choose k) + (u * (Sum Q))) <= 1 + ((n choose k) + (u * (Sum Q))) by XREAL_1:7;
then (Sum I1) / (u |^ k) < 1 + ((n choose k) + (u * (Sum Q))) by A40, XXREAL_0:2;
then A41: ((Sum I1) / (u |^ k)) - 1 < (n choose k) + (u * (Sum Q)) by XREAL_1:19;
A42: 0 + ((I1 . (k + 1)) + (Sum q)) <= (Sum (I1 | k)) + ((I1 . (k + 1)) + (Sum q)) by XREAL_1:7;
(I1 . (k + 1)) + (Sum q) = (u |^ k) * ((n choose k) + (u * (Sum Q))) by A33, A19;
then (Sum I1) / (u |^ k) >= (n choose k) + (u * (Sum Q)) by A1, A42, A6, XREAL_1:77;
hence [\((Sum I1) / (u |^ k))/] = (n choose k) + (u * (Sum Q)) by A41, INT_1:def 6; :: thesis: verum
end;
end;
end;
A43: Sum I1 = (1 + u) |^ n by NEWTON:30;
n choose k <= n |^ k by Th13, A1;
then n choose k < u by A1, XXREAL_0:2;
then (n choose k) mod u = n choose k by NAT_D:24;
hence [\(((u + 1) |^ n) / (u |^ k))/] mod u = n choose k by A34, A43, NAT_D:21; :: thesis: verum