let T be _Tree; for P being Path of T
for i, j being odd Nat st i < j & j <= len P holds
P . i <> P . j
let P be Path of T; for i, j being odd Nat st i < j & j <= len P holds
P . i <> P . j
let i, j be odd Nat; ( i < j & j <= len P implies P . i <> P . j )
assume that
A1:
i < j
and
A2:
j <= len P
and
A3:
P . i = P . j
; contradiction
reconsider i = i, j = j as odd Element of NAT by ORDINAL1:def 12;
A4:
i < j
by A1;
then A5:
i = 1
by A2, A3, GLIB_001:def 28;
then A6:
P is trivial
by A1, A2, GLIB_001:126;
P .first() = P .last()
by A2, A3, A4, A5, GLIB_001:def 28;
hence
contradiction
by A6, GLIB_001:def 24; verum