let S be satisfying_CongruenceSymmetry satisfying_CongruenceEquivalenceRelation TarskiGeometryStruct ; ( S is satisfying_SAS iff S is satisfying_SST_A5 )
thus
( S is satisfying_SAS implies S is satisfying_SST_A5 )
( S is satisfying_SST_A5 implies S is satisfying_SAS )proof
assume A1:
S is
satisfying_SAS
;
S is satisfying_SST_A5
now for a, b, c, d, a9, b9, c9, d9 being POINT of S st a <> b & between a,b,c & between a9,b9,c9 & a,b equiv a9,b9 & b,c equiv b9,c9 & a,d equiv a9,d9 & b,d equiv b9,d9 holds
c,d equiv c9,d9let a,
b,
c,
d,
a9,
b9,
c9,
d9 be
POINT of
S;
( a <> b & between a,b,c & between a9,b9,c9 & a,b equiv a9,b9 & b,c equiv b9,c9 & a,d equiv a9,d9 & b,d equiv b9,d9 implies c,d equiv c9,d9 )assume A2:
(
a <> b &
between a,
b,
c &
between a9,
b9,
c9 &
a,
b equiv a9,
b9 &
b,
c equiv b9,
c9 &
a,
d equiv a9,
d9 &
b,
d equiv b9,
d9 )
;
c,d equiv c9,d9then
a,
b,
d cong a9,
b9,
d9
;
then
d,
c equiv d9,
c9
by A1, A2;
then
c,
d equiv d9,
c9
by Satz2p4;
hence
c,
d equiv c9,
d9
by Satz2p5;
verum end;
hence
S is
satisfying_SST_A5
;
verum
end;
thus
( S is satisfying_SST_A5 implies S is satisfying_SAS )
verumproof
assume A3:
S is
satisfying_SST_A5
;
S is satisfying_SAS
now for a, b, c, x, a1, b1, c1, x1 being POINT of S st a <> b & a,b,c cong a1,b1,c1 & between a,b,x & between a1,b1,x1 & b,x equiv b1,x1 holds
c,x equiv c1,x1let a,
b,
c,
x,
a1,
b1,
c1,
x1 be
POINT of
S;
( a <> b & a,b,c cong a1,b1,c1 & between a,b,x & between a1,b1,x1 & b,x equiv b1,x1 implies c,x equiv c1,x1 )assume
(
a <> b &
a,
b,
c cong a1,
b1,
c1 &
between a,
b,
x &
between a1,
b1,
x1 &
b,
x equiv b1,
x1 )
;
c,x equiv c1,x1then
x,
c equiv x1,
c1
by A3;
then
c,
x equiv x1,
c1
by Satz2p4;
hence
c,
x equiv c1,
x1
by Satz2p5;
verum end;
hence
S is
satisfying_SAS
;
verum
end;