let G, H be strict Group; for h being Homomorphism of G,H st G is solvable Group holds
Image h is solvable
let h be Homomorphism of G,H; ( G is solvable Group implies Image h is solvable )
assume
G is solvable Group
; Image h is solvable
then consider F being FinSequence of Subgroups G such that
A1:
len F > 0
and
A2:
F . 1 = (Omega). G
and
A3:
F . (len F) = (1). G
and
A4:
for i being Element of NAT st i in dom F & i + 1 in dom F holds
for G1, G2 being strict Subgroup of G st G1 = F . i & G2 = F . (i + 1) holds
( G2 is strict normal Subgroup of G1 & ( for N being normal Subgroup of G1 st N = G2 holds
G1 ./. N is commutative ) )
by Def1;
1 <= len F
by A1, NAT_1:14;
then A5:
1 in Seg (len F)
by FINSEQ_1:1;
defpred S1[ set , set ] means ex J being strict Subgroup of G st
( J = F . $1 & $2 = h .: J );
A6:
for k being Nat st k in Seg (len F) holds
ex x being Element of Subgroups (Image h) st S1[k,x]
consider z being FinSequence of Subgroups (Image h) such that
A8:
( dom z = Seg (len F) & ( for j being Nat st j in Seg (len F) holds
S1[j,z . j] ) )
from FINSEQ_1:sch 5(A6);
Seg (len z) = Seg (len F)
by A8, FINSEQ_1:def 3;
then A9: dom F =
Seg (len z)
by FINSEQ_1:def 3
.=
dom z
by FINSEQ_1:def 3
;
A10:
for i being Element of NAT st i in dom z & i + 1 in dom z holds
for G1, G2 being strict Subgroup of Image h st G1 = z . i & G2 = z . (i + 1) holds
( G2 is strict normal Subgroup of G1 & ( for N being normal Subgroup of G1 st N = G2 holds
G1 ./. N is commutative ) )
proof
let i be
Element of
NAT ;
( i in dom z & i + 1 in dom z implies for G1, G2 being strict Subgroup of Image h st G1 = z . i & G2 = z . (i + 1) holds
( G2 is strict normal Subgroup of G1 & ( for N being normal Subgroup of G1 st N = G2 holds
G1 ./. N is commutative ) ) )
assume that A11:
i in dom z
and A12:
i + 1
in dom z
;
for G1, G2 being strict Subgroup of Image h st G1 = z . i & G2 = z . (i + 1) holds
( G2 is strict normal Subgroup of G1 & ( for N being normal Subgroup of G1 st N = G2 holds
G1 ./. N is commutative ) )
let G1,
G2 be
strict Subgroup of
Image h;
( G1 = z . i & G2 = z . (i + 1) implies ( G2 is strict normal Subgroup of G1 & ( for N being normal Subgroup of G1 st N = G2 holds
G1 ./. N is commutative ) ) )
assume that A13:
G1 = z . i
and A14:
G2 = z . (i + 1)
;
( G2 is strict normal Subgroup of G1 & ( for N being normal Subgroup of G1 st N = G2 holds
G1 ./. N is commutative ) )
consider A being
strict Subgroup of
G such that A15:
A = F . i
and A16:
G1 = h .: A
by A8, A11, A13;
consider B being
strict Subgroup of
G such that A17:
B = F . (i + 1)
and A18:
G2 = h .: B
by A8, A12, A14;
A19:
for
N being
normal Subgroup of
G1 st
N = G2 holds
G1 ./. N is
commutative
proof
let N be
normal Subgroup of
G1;
( N = G2 implies G1 ./. N is commutative )
assume A20:
N = G2
;
G1 ./. N is commutative
now for x, y being Element of (G1 ./. N) holds x * y = y * xlet x,
y be
Element of
(G1 ./. N);
x * y = y * x
x in G1 ./. N
by STRUCT_0:def 5;
then consider a being
Element of
G1 such that A21:
x = a * N
and
x = N * a
by GROUP_6:23;
y in G1 ./. N
by STRUCT_0:def 5;
then consider b being
Element of
G1 such that A22:
y = b * N
and
y = N * b
by GROUP_6:23;
x in the
carrier of
(G1 ./. N)
;
then A23:
x in Cosets N
by GROUP_6:17;
then reconsider x1 =
x as
Subset of
G1 ;
b in h .: A
by A16, STRUCT_0:def 5;
then consider b1 being
Element of
A such that A24:
b = (h | A) . b1
by GROUP_6:45;
reconsider b1 =
b1 as
Element of
G by GROUP_2:42;
b = h . b1
by A24, FUNCT_1:49;
then A25:
b * N =
(h . b1) * (h .: B)
by A18, A20, GROUP_6:2
.=
h .: (b1 * B)
by Th13
;
then reconsider y2 =
h .: (b1 * B) as
Subset of
G1 ;
a in h .: A
by A16, STRUCT_0:def 5;
then consider a1 being
Element of
A such that A26:
a = (h | A) . a1
by GROUP_6:45;
reconsider a1 =
a1 as
Element of
G by GROUP_2:42;
a = h . a1
by A26, FUNCT_1:49;
then A27:
a * N =
(h . a1) * (h .: B)
by A18, A20, GROUP_6:2
.=
h .: (a1 * B)
by Th13
;
then reconsider x2 =
h .: (a1 * B) as
Subset of
G1 ;
then A31:
x2 * y2 c= (h .: (a1 * B)) * (h .: (b1 * B))
;
A32:
(a1 * B) * (b1 * B) = (b1 * B) * (a1 * B)
proof
reconsider K =
B as
normal Subgroup of
A by A4, A9, A11, A12, A15, A17;
reconsider a2 =
a1,
b2 =
b1 as
Element of
A ;
A33:
a1 * B = a2 * K
by GROUP_6:2;
then reconsider A1 =
a1 * B as
Subset of
A ;
A34:
b1 * B = b2 * K
by GROUP_6:2;
then reconsider B1 =
b1 * B as
Subset of
A ;
reconsider a12 =
a1 * B,
b12 =
b1 * B as
Element of
Cosets K by A33, A34, GROUP_6:14;
a2 * K is
Element of
(A ./. K)
by GROUP_6:22;
then reconsider a11 =
a12 as
Element of
(A ./. K) by GROUP_6:2;
b2 * K is
Element of
(A ./. K)
by GROUP_6:22;
then reconsider b11 =
b12 as
Element of
(A ./. K) by GROUP_6:2;
now for x being object st x in (a1 * B) * (b1 * B) holds
x in A1 * B1let x be
object ;
( x in (a1 * B) * (b1 * B) implies x in A1 * B1 )assume
x in (a1 * B) * (b1 * B)
;
x in A1 * B1then consider z1,
z2 being
Element of
G such that A35:
x = z1 * z2
and A36:
(
z1 in a1 * B &
z2 in b1 * B )
;
(
z1 in A1 &
z2 in B1 )
by A36;
then reconsider z11 =
z1,
z22 =
z2 as
Element of
A ;
z1 * z2 = z11 * z22
by GROUP_2:43;
hence
x in A1 * B1
by A35, A36;
verum end;
then A37:
(a1 * B) * (b1 * B) c= A1 * B1
;
now for x being object st x in (b1 * B) * (a1 * B) holds
x in B1 * A1let x be
object ;
( x in (b1 * B) * (a1 * B) implies x in B1 * A1 )assume
x in (b1 * B) * (a1 * B)
;
x in B1 * A1then consider z1,
z2 being
Element of
G such that A38:
x = z1 * z2
and A39:
(
z1 in b1 * B &
z2 in a1 * B )
;
(
z1 in B1 &
z2 in A1 )
by A39;
then reconsider z11 =
z1,
z22 =
z2 as
Element of
A ;
z1 * z2 = z11 * z22
by GROUP_2:43;
hence
x in B1 * A1
by A38, A39;
verum end;
then A40:
(b1 * B) * (a1 * B) c= B1 * A1
;
then A43:
B1 * A1 c= (b1 * B) * (a1 * B)
;
A44:
A ./. K is
commutative Group
by A4, A9, A11, A12, A15, A17;
A45:
for
a,
b being
Element of
(A ./. K) holds the
multF of
(A ./. K) . (
a,
b)
= the
multF of
(A ./. K) . (
b,
a)
by A44, BINOP_1:def 2, GROUP_3:2;
A46:
A1 * B1 =
(CosOp K) . (
a11,
b11)
by GROUP_6:def 3
.=
the
multF of
(A ./. K) . (
a12,
b12)
by GROUP_6:18
.=
the
multF of
(A ./. K) . (
b11,
a11)
by A45
.=
(CosOp K) . (
b12,
a12)
by GROUP_6:18
.=
B1 * A1
by GROUP_6:def 3
;
then
A1 * B1 c= (a1 * B) * (b1 * B)
;
then
(a1 * B) * (b1 * B) = A1 * B1
by A37, XBOOLE_0:def 10;
hence
(a1 * B) * (b1 * B) = (b1 * B) * (a1 * B)
by A46, A40, A43, XBOOLE_0:def 10;
verum
end; then A52:
y2 * x2 c= (h .: (b1 * B)) * (h .: (a1 * B))
;
A53:
(h .: (b1 * B)) * (h .: (a1 * B)) = h .: ((b1 * B) * (a1 * B))
by Th14;
then
(h .: (b1 * B)) * (h .: (a1 * B)) c= y2 * x2
;
then A62:
y2 * x2 = (h .: (b1 * B)) * (h .: (a1 * B))
by A52, XBOOLE_0:def 10;
A63:
(h .: (a1 * B)) * (h .: (b1 * B)) = h .: ((a1 * B) * (b1 * B))
by Th14;
then
(h .: (a1 * B)) * (h .: (b1 * B)) c= x2 * y2
;
then A72:
x2 * y2 = (h .: (a1 * B)) * (h .: (b1 * B))
by A31, XBOOLE_0:def 10;
y in the
carrier of
(G1 ./. N)
;
then A73:
y in Cosets N
by GROUP_6:17;
then reconsider y1 =
y as
Subset of
G1 ;
thus x * y =
(CosOp N) . (
x,
y)
by GROUP_6:18
.=
y1 * x1
by A23, A73, A21, A22, A27, A25, A63, A72, A53, A62, A32, GROUP_6:def 3
.=
(CosOp N) . (
y,
x)
by A23, A73, GROUP_6:def 3
.=
y * x
by GROUP_6:18
;
verum end;
hence
G1 ./. N is
commutative
by GROUP_1:def 12;
verum
end;
B is
strict normal Subgroup of
A
by A4, A9, A11, A12, A15, A17;
hence
(
G2 is
strict normal Subgroup of
G1 & ( for
N being
normal Subgroup of
G1 st
N = G2 holds
G1 ./. N is
commutative ) )
by A16, A18, A19, Th15;
verum
end;
take
z
; GRSOLV_1:def 1 ( len z > 0 & z . 1 = (Omega). (Image h) & z . (len z) = (1). (Image h) & ( for i being Element of NAT st i in dom z & i + 1 in dom z holds
for G1, G2 being strict Subgroup of Image h st G1 = z . i & G2 = z . (i + 1) holds
( G2 is strict normal Subgroup of G1 & ( for N being normal Subgroup of G1 st N = G2 holds
G1 ./. N is commutative ) ) ) )
A74:
len z = len F
by A8, FINSEQ_1:def 3;
( z . 1 = (Omega). (Image h) & z . (len z) = (1). (Image h) )
hence
( len z > 0 & z . 1 = (Omega). (Image h) & z . (len z) = (1). (Image h) & ( for i being Element of NAT st i in dom z & i + 1 in dom z holds
for G1, G2 being strict Subgroup of Image h st G1 = z . i & G2 = z . (i + 1) holds
( G2 is strict normal Subgroup of G1 & ( for N being normal Subgroup of G1 st N = G2 holds
G1 ./. N is commutative ) ) ) )
by A1, A8, A10, FINSEQ_1:def 3; verum