let O be non empty set ; for E being set
for o being Element of O
for F being FinSequence of O
for A being Action of O,E holds Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))
let E be set ; for o being Element of O
for F being FinSequence of O
for A being Action of O,E holds Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))
let o be Element of O; for F being FinSequence of O
for A being Action of O,E holds Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))
let F be FinSequence of O; for A being Action of O,E holds Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))
let A be Action of O,E; Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))
defpred S1[ Nat] means for F being FinSequence of O st len F = $1 holds
Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A));
reconsider k = len F as Element of NAT ;
A1:
k = len F
;
A2:
for k being Nat st S1[k] holds
S1[k + 1]
proof
let k be
Nat;
( S1[k] implies S1[k + 1] )
assume A3:
S1[
k]
;
S1[k + 1]
now for F being FinSequence of O st len F = k + 1 holds
Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))let F be
FinSequence of
O;
( len F = k + 1 implies Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A)) )assume A4:
len F = k + 1
;
Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))then consider Fk being
FinSequence of
O,
o9 being
Element of
O such that A5:
F = Fk ^ <*o9*>
by FINSEQ_2:19;
len F = (len Fk) + (len <*o9*>)
by A5, FINSEQ_1:22;
then A6:
k + 1
= (len Fk) + 1
by A4, FINSEQ_1:39;
set F2k =
<*o*> ^ Fk;
thus Product (
(<*o*> ^ F),
A) =
Product (
((<*o*> ^ Fk) ^ <*o9*>),
A)
by A5, FINSEQ_1:32
.=
(Product ((<*o*> ^ Fk),A)) * (Product (<*o9*>,A))
by Lm26
.=
((Product (<*o*>,A)) * (Product (Fk,A))) * (Product (<*o9*>,A))
by A3, A6
.=
(Product (<*o*>,A)) * ((Product (Fk,A)) * (Product (<*o9*>,A)))
by RELAT_1:36
.=
(Product (<*o*>,A)) * (Product (F,A))
by A5, Lm26
;
verum end;
hence
S1[
k + 1]
;
verum
end;
A7:
S1[ 0 ]
proof
let F be
FinSequence of
O;
( len F = 0 implies Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A)) )
assume A8:
len F = 0
;
Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))
then
F = <*> O
;
hence Product (
(<*o*> ^ F),
A) =
Product (
<*o*>,
A)
by FINSEQ_1:34
.=
(Product (<*o*>,A)) * (id E)
by FUNCT_2:17
.=
(Product (<*o*>,A)) * (Product (F,A))
by A8, Def3
;
verum
end;
for k being Nat holds S1[k]
from NAT_1:sch 2(A7, A2);
hence
Product ((<*o*> ^ F),A) = (Product (<*o*>,A)) * (Product (F,A))
by A1; verum