let f1, f2 be CompositionSeries of G; ( ( for k, i, j being Nat
for H1, H2, H3 being StableSubgroup of G holds
( ( k = ((i - 1) * ((len s2) - 1)) + j & 1 <= i & i <= (len s1) - 1 & 1 <= j & j <= (len s2) - 1 & H1 = s1 . (i + 1) & H2 = s1 . i & H3 = s2 . j implies f1 . k = H1 "\/" (H2 /\ H3) ) & ( k = (((len s1) - 1) * ((len s2) - 1)) + 1 implies f1 . k = (1). G ) & len f1 = (((len s1) - 1) * ((len s2) - 1)) + 1 ) ) & ( for k, i, j being Nat
for H1, H2, H3 being StableSubgroup of G holds
( ( k = ((i - 1) * ((len s2) - 1)) + j & 1 <= i & i <= (len s1) - 1 & 1 <= j & j <= (len s2) - 1 & H1 = s1 . (i + 1) & H2 = s1 . i & H3 = s2 . j implies f2 . k = H1 "\/" (H2 /\ H3) ) & ( k = (((len s1) - 1) * ((len s2) - 1)) + 1 implies f2 . k = (1). G ) & len f2 = (((len s1) - 1) * ((len s2) - 1)) + 1 ) ) implies f1 = f2 )
assume A104:
for k, i, j being Nat
for H1, H2, H3 being StableSubgroup of G holds
( ( k = ((i - 1) * ((len s2) - 1)) + j & 1 <= i & i <= (len s1) - 1 & 1 <= j & j <= (len s2) - 1 & H1 = s1 . (i + 1) & H2 = s1 . i & H3 = s2 . j implies f1 . k = H1 "\/" (H2 /\ H3) ) & ( k = (((len s1) - 1) * ((len s2) - 1)) + 1 implies f1 . k = (1). G ) & len f1 = (((len s1) - 1) * ((len s2) - 1)) + 1 )
; ( ex k, i, j being Nat ex H1, H2, H3 being StableSubgroup of G st
( ( k = ((i - 1) * ((len s2) - 1)) + j & 1 <= i & i <= (len s1) - 1 & 1 <= j & j <= (len s2) - 1 & H1 = s1 . (i + 1) & H2 = s1 . i & H3 = s2 . j implies f2 . k = H1 "\/" (H2 /\ H3) ) & ( k = (((len s1) - 1) * ((len s2) - 1)) + 1 implies f2 . k = (1). G ) implies not len f2 = (((len s1) - 1) * ((len s2) - 1)) + 1 ) or f1 = f2 )
assume A105:
for k, i, j being Nat
for H1, H2, H3 being StableSubgroup of G holds
( ( k = ((i - 1) * ((len s2) - 1)) + j & 1 <= i & i <= (len s1) - 1 & 1 <= j & j <= (len s2) - 1 & H1 = s1 . (i + 1) & H2 = s1 . i & H3 = s2 . j implies f2 . k = H1 "\/" (H2 /\ H3) ) & ( k = (((len s1) - 1) * ((len s2) - 1)) + 1 implies f2 . k = (1). G ) & len f2 = (((len s1) - 1) * ((len s2) - 1)) + 1 )
; f1 = f2
dom f1 =
Seg (len f2)
by A104, A105, FINSEQ_1:def 3
.=
dom f2
by FINSEQ_1:def 3
;
hence
f1 = f2
by A106, FINSEQ_1:13; verum