let O be set ; for G being GroupWithOperators of O
for H1, H2 being StableSubgroup of G
for s1 being CompositionSeries of G
for i, j being Nat st i in dom s1 & j in dom s1 & i <= j & H1 = s1 . i & H2 = s1 . j holds
H2 is StableSubgroup of H1
let G be GroupWithOperators of O; for H1, H2 being StableSubgroup of G
for s1 being CompositionSeries of G
for i, j being Nat st i in dom s1 & j in dom s1 & i <= j & H1 = s1 . i & H2 = s1 . j holds
H2 is StableSubgroup of H1
let H1, H2 be StableSubgroup of G; for s1 being CompositionSeries of G
for i, j being Nat st i in dom s1 & j in dom s1 & i <= j & H1 = s1 . i & H2 = s1 . j holds
H2 is StableSubgroup of H1
let s1 be CompositionSeries of G; for i, j being Nat st i in dom s1 & j in dom s1 & i <= j & H1 = s1 . i & H2 = s1 . j holds
H2 is StableSubgroup of H1
let i, j be Nat; ( i in dom s1 & j in dom s1 & i <= j & H1 = s1 . i & H2 = s1 . j implies H2 is StableSubgroup of H1 )
assume that
A1:
i in dom s1
and
A2:
j in dom s1
; ( not i <= j or not H1 = s1 . i or not H2 = s1 . j or H2 is StableSubgroup of H1 )
defpred S1[ Nat] means for n being Nat
for H2 being StableSubgroup of G st i + $1 in dom s1 & H2 = s1 . (i + $1) holds
H2 is StableSubgroup of H1;
assume A3:
i <= j
; ( not H1 = s1 . i or not H2 = s1 . j or H2 is StableSubgroup of H1 )
assume that
A4:
H1 = s1 . i
and
A5:
H2 = s1 . j
; H2 is StableSubgroup of H1
A6:
for n being Nat st S1[n] holds
S1[n + 1]
proof
let n be
Nat;
( S1[n] implies S1[n + 1] )
assume A7:
S1[
n]
;
S1[n + 1]
set H2 =
s1 . (i + n);
end;
A14:
S1[ 0 ]
by A4, Th10;
A15:
for n being Nat holds S1[n]
from NAT_1:sch 2(A14, A6);
set n = j - i;
i - i <= j - i
by A3, XREAL_1:9;
then reconsider n = j - i as Element of NAT by INT_1:3;
reconsider n = n as Nat ;
j = i + n
;
hence
H2 is StableSubgroup of H1
by A2, A5, A15; verum