let A, B, A1, B1 be set ; ( A misses B & A1 c= A & B1 c= B & A1 \/ B1 = A \/ B implies ( A1 = A & B1 = B ) )
assume A1:
A misses B
; ( not A1 c= A or not B1 c= B or not A1 \/ B1 = A \/ B or ( A1 = A & B1 = B ) )
assume A2:
( A1 c= A & B1 c= B )
; ( not A1 \/ B1 = A \/ B or ( A1 = A & B1 = B ) )
assume A3:
A1 \/ B1 = A \/ B
; ( A1 = A & B1 = B )
A4:
A c= A1
B c= B1
hence
( A1 = A & B1 = B )
by A2, XBOOLE_0:def 10, A4; verum