let F1, F2 be Nat; ( ( X <> {} implies ex i being Nat st
( i = F1 & i in X & ( for k being Nat st k in X holds
f /. ((2 * n) + i) <= f /. ((2 * n) + k) ) & ( for k being Nat st k in X & f /. ((2 * n) + i) = f /. ((2 * n) + k) holds
i <= k ) ) ) & ( X = {} implies F1 = 0 ) & ( X <> {} implies ex i being Nat st
( i = F2 & i in X & ( for k being Nat st k in X holds
f /. ((2 * n) + i) <= f /. ((2 * n) + k) ) & ( for k being Nat st k in X & f /. ((2 * n) + i) = f /. ((2 * n) + k) holds
i <= k ) ) ) & ( X = {} implies F2 = 0 ) implies F1 = F2 )
assume that
A6:
( X <> {} implies ex i being Nat st
( i = F1 & i in X & ( for k being Nat st k in X holds
f /. ((2 * n) + i) <= f /. ((2 * n) + k) ) & ( for k being Nat st k in X & f /. ((2 * n) + i) = f /. ((2 * n) + k) holds
i <= k ) ) )
and
A7:
( X = {} implies F1 = 0 )
and
A8:
( X <> {} implies ex i being Nat st
( i = F2 & i in X & ( for k being Nat st k in X holds
f /. ((2 * n) + i) <= f /. ((2 * n) + k) ) & ( for k being Nat st k in X & f /. ((2 * n) + i) = f /. ((2 * n) + k) holds
i <= k ) ) )
and
A9:
( X = {} implies F2 = 0 )
; F1 = F2