let I be non empty set ; for H being Group-like associative multMagma-Family of I
for k being Nat
for s being Element of (FreeProduct H) st k <= len (nf s) holds
ex s1, s2 being Element of (FreeProduct H) st
( s = s1 * s2 & nf s = (nf s1) ^ (nf s2) & len (nf s1) = k )
let H be Group-like associative multMagma-Family of I; for k being Nat
for s being Element of (FreeProduct H) st k <= len (nf s) holds
ex s1, s2 being Element of (FreeProduct H) st
( s = s1 * s2 & nf s = (nf s1) ^ (nf s2) & len (nf s1) = k )
let k be Nat; for s being Element of (FreeProduct H) st k <= len (nf s) holds
ex s1, s2 being Element of (FreeProduct H) st
( s = s1 * s2 & nf s = (nf s1) ^ (nf s2) & len (nf s1) = k )
let s be Element of (FreeProduct H); ( k <= len (nf s) implies ex s1, s2 being Element of (FreeProduct H) st
( s = s1 * s2 & nf s = (nf s1) ^ (nf s2) & len (nf s1) = k ) )
assume A1:
k <= len (nf s)
; ex s1, s2 being Element of (FreeProduct H) st
( s = s1 * s2 & nf s = (nf s1) ^ (nf s2) & len (nf s1) = k )
set s1 = Class ((EqCl (ReductionRel H)),((nf s) | k));
(nf s) | k in (FreeAtoms H) *
by FINSEQ_1:def 11;
then
(nf s) | k is Element of ((FreeAtoms H) *+^+<0>)
by MONOID_0:61;
then reconsider s1 = Class ((EqCl (ReductionRel H)),((nf s) | k)) as Element of (FreeProduct H) by EQREL_1:def 3;
set s2 = Class ((EqCl (ReductionRel H)),((nf s) /^ k));
(nf s) /^ k in (FreeAtoms H) *
by FINSEQ_1:def 11;
then
(nf s) /^ k is Element of ((FreeAtoms H) *+^+<0>)
by MONOID_0:61;
then reconsider s2 = Class ((EqCl (ReductionRel H)),((nf s) /^ k)) as Element of (FreeProduct H) by EQREL_1:def 3;
take
s1
; ex s2 being Element of (FreeProduct H) st
( s = s1 * s2 & nf s = (nf s1) ^ (nf s2) & len (nf s1) = k )
take
s2
; ( s = s1 * s2 & nf s = (nf s1) ^ (nf s2) & len (nf s1) = k )
consider y being Element of ((FreeAtoms H) *+^+<0>) such that
A2:
s = Class ((EqCl (ReductionRel H)),y)
by EQREL_1:36;
nf s in s
by Def7;
hence s =
Class ((EqCl (ReductionRel H)),(nf s))
by A2, EQREL_1:23
.=
Class ((EqCl (ReductionRel H)),(((nf s) | k) ^ ((nf s) /^ k)))
by RFINSEQ:8
.=
s1 * s2
by Th47
;
( nf s = (nf s1) ^ (nf s2) & len (nf s1) = k )
thus nf s =
((nf s) | k) ^ ((nf s) /^ k)
by RFINSEQ:8
.=
(nf s1) ^ ((nf s) /^ k)
by Th60
.=
(nf s1) ^ (nf s2)
by Th61
; len (nf s1) = k
nf s1 = (nf s) | k
by Th60;
hence
len (nf s1) = k
by A1, FINSEQ_1:59; verum