let p, q, p1 be Point of (TOP-REAL 2); ( p `1 <= q `1 & q `1 <= p1 `1 & p `2 = q `2 & q `2 = p1 `2 implies q in LSeg (p,p1) )
assume that
A1:
( p `1 <= q `1 & q `1 <= p1 `1 )
and
A2:
p `2 = q `2
and
A3:
q `2 = p1 `2
; q in LSeg (p,p1)
A4:
p `1 <= p1 `1
by A1, XXREAL_0:2;
per cases
( p `1 = p1 `1 or p `1 < p1 `1 )
by A4, XXREAL_0:1;
suppose A5:
p `1 = p1 `1
;
q in LSeg (p,p1)then
p `1 = q `1
by A1, XXREAL_0:1;
then A6:
q =
|[(p `1),(p `2)]|
by A2, EUCLID:53
.=
p
by EUCLID:53
;
p =
|[(p1 `1),(p1 `2)]|
by A2, A3, A5, EUCLID:53
.=
p1
by EUCLID:53
;
then
LSeg (
p,
p1)
= {p}
by RLTOPSP1:70;
hence
q in LSeg (
p,
p1)
by A6, TARSKI:def 1;
verum end; end;