let p, q, p1 be Point of (TOP-REAL 2); ( p `1 = q `1 & q `1 = p1 `1 & p `2 <= q `2 & q `2 <= p1 `2 implies q in LSeg (p,p1) )
assume that
A1:
p `1 = q `1
and
A2:
q `1 = p1 `1
and
A3:
( p `2 <= q `2 & q `2 <= p1 `2 )
; q in LSeg (p,p1)
A4:
p `2 <= p1 `2
by A3, XXREAL_0:2;
per cases
( p `2 = p1 `2 or p `2 < p1 `2 )
by A4, XXREAL_0:1;
suppose A5:
p `2 = p1 `2
;
q in LSeg (p,p1)then
p `2 = q `2
by A3, XXREAL_0:1;
then A6:
q =
|[(p `1),(p `2)]|
by A1, EUCLID:53
.=
p
by EUCLID:53
;
p =
|[(p1 `1),(p1 `2)]|
by A1, A2, A5, EUCLID:53
.=
p1
by EUCLID:53
;
then
LSeg (
p,
p1)
= {p}
by RLTOPSP1:70;
hence
q in LSeg (
p,
p1)
by A6, TARSKI:def 1;
verum end; end;