let f be circular s.c.c. FinSequence of (TOP-REAL 2); :: thesis: ( len f > 4 implies for i, j being Nat st 1 <= i & i < j & j < len f holds
f /. i <> f /. j )

assume A1: len f > 4 ; :: thesis: for i, j being Nat st 1 <= i & i < j & j < len f holds
f /. i <> f /. j

let i, j be Nat; :: thesis: ( 1 <= i & i < j & j < len f implies f /. i <> f /. j )
assume that
A2: 1 <= i and
A3: i < j and
A4: j < len f and
A5: f /. i = f /. j ; :: thesis: contradiction
A6: j + 1 <= len f by A4, NAT_1:13;
A7: ( i + 1 <= j & i <> 0 ) by A2, A3, NAT_1:13;
1 <= j by A2, A3, XXREAL_0:2;
then A8: f /. j in LSeg (f,j) by A6, TOPREAL1:21;
A9: i < len f by A3, A4, XXREAL_0:2;
then i + 1 <= len f by NAT_1:13;
then A10: f /. i in LSeg (f,i) by A2, TOPREAL1:21;
( i <= 2 implies not not i = 0 & ... & not i = 2 ) ;
per cases then ( ( i + 1 = j & i = 1 ) or ( i + 1 = j & i = 1 + 1 ) or i > 1 + 1 or ( i + 1 < j & i <> 1 ) or ( i + 1 < j & j + 1 <> len f ) or ( i + 1 < j & i = 1 & j + 1 = len f ) ) by A7, XXREAL_0:1;
suppose that A11: i + 1 = j and
A12: i = 1 ; :: thesis: contradiction
end;
suppose that A17: i + 1 = j and
A18: i = 1 + 1 ; :: thesis: contradiction
end;
suppose A21: i > 1 + 1 ; :: thesis: contradiction
end;
suppose that A25: i + 1 < j and
A26: i <> 1 ; :: thesis: contradiction
end;
suppose that A27: i + 1 < j and
A28: j + 1 <> len f ; :: thesis: contradiction
end;
suppose that A29: i + 1 < j and
A30: i = 1 and
A31: j + 1 = len f ; :: thesis: contradiction
end;
end;