let G be _Graph; for W1, W2 being Walk of G st W1 is Subwalk of W2 holds
for m being odd Element of NAT st m <= len W1 holds
ex n being odd Element of NAT st
( m <= n & n <= len W2 & W1 . m = W2 . n )
let W1, W2 be Walk of G; ( W1 is Subwalk of W2 implies for m being odd Element of NAT st m <= len W1 holds
ex n being odd Element of NAT st
( m <= n & n <= len W2 & W1 . m = W2 . n ) )
assume A1:
W1 is Subwalk of W2
; for m being odd Element of NAT st m <= len W1 holds
ex n being odd Element of NAT st
( m <= n & n <= len W2 & W1 . m = W2 . n )
let m be odd Element of NAT ; ( m <= len W1 implies ex n being odd Element of NAT st
( m <= n & n <= len W2 & W1 . m = W2 . n ) )
assume A2:
m <= len W1
; ex n being odd Element of NAT st
( m <= n & n <= len W2 & W1 . m = W2 . n )
A3:
ex es being Subset of (W2 .edgeSeq()) st W1 .edgeSeq() = Seq es
by A1, Def32;
now ex n being odd Element of NAT st
( m <= n & n <= len W2 & W1 . m = W2 . n )per cases
( m < len W1 or m = len W1 )
by A2, XXREAL_0:1;
suppose A4:
m < len W1
;
ex n being odd Element of NAT st
( m <= n & n <= len W2 & W1 . m = W2 . n )then A5:
W1 . (m + 1) Joins W1 . m,
W1 . (m + 2),
G
by Def3;
reconsider m1 =
m + 1 as
even Element of
NAT ;
A6:
1
<= m1
by NAT_1:12;
A7:
m1 <= len W1
by A4, NAT_1:13;
then A8:
W1 . m1 = (W1 .edgeSeq()) . (m1 div 2)
by A6, Lm40;
m1 div 2
in dom (W1 .edgeSeq())
by A6, A7, Lm40;
then consider x being
Element of
NAT such that A9:
x in dom (W2 .edgeSeq())
and A10:
m1 div 2
<= x
and A11:
W1 . m1 = (W2 .edgeSeq()) . x
by A3, A8, Th3;
set n = 2
* x;
A12:
1
<= x
by A9, FINSEQ_3:25;
2
divides m1
by PEPIN:22;
then
2
* (m1 div 2) = m1
by NAT_D:3;
then
m1 <= 2
* x
by A10, XREAL_1:64;
then A13:
m1 - 1
<= (2 * x) - 1
by XREAL_1:13;
A14:
x <= len (W2 .edgeSeq())
by A9, FINSEQ_3:25;
A15:
2
* x in dom W2
by A9, Lm41;
then
1
<= 2
* x
by FINSEQ_3:25;
then reconsider naa1 =
(2 * x) - 1 as
odd Element of
NAT by INT_1:5;
2
* x <= len W2
by A15, FINSEQ_3:25;
then A16:
naa1 < (len W2) - 0
by XREAL_1:15;
then
W2 . (naa1 + 1) Joins W2 . naa1,
W2 . (naa1 + 2),
G
by Def3;
then A17:
W1 . m1 Joins W2 . naa1,
W2 . (naa1 + 2),
G
by A11, A12, A14, Def15;
A18:
naa1 + 2
<= len W2
by A16, Th1;
hence
ex
n being
odd Element of
NAT st
(
m <= n &
n <= len W2 &
W1 . m = W2 . n )
;
verum end; end; end;
hence
ex n being odd Element of NAT st
( m <= n & n <= len W2 & W1 . m = W2 . n )
; verum