let G be _Graph; for W being Walk of G
for m, n being odd Element of NAT st m <= n & n <= len W holds
( W .cut (m,n) is trivial iff m = n )
let W be Walk of G; for m, n being odd Element of NAT st m <= n & n <= len W holds
( W .cut (m,n) is trivial iff m = n )
let m, n be odd Element of NAT ; ( m <= n & n <= len W implies ( W .cut (m,n) is trivial iff m = n ) )
assume that
A1:
m <= n
and
A2:
n <= len W
; ( W .cut (m,n) is trivial iff m = n )
A3:
(len (W .cut (m,n))) + m = n + 1
by A1, A2, Lm15;
assume
m = n
; W .cut (m,n) is trivial
hence
W .cut (m,n) is trivial
by A3, Lm55; verum