let G be _Graph; for V1, V2, E1, E2 being set
for G1 being inducedSubgraph of G,V1,E1
for G2 being inducedSubgraph of G,V2,E2 st V2 c= V1 & E2 c= E1 & V2 is non empty Subset of (the_Vertices_of G) & E2 c= G .edgesBetween V2 holds
G2 is Subgraph of G1
let V1, V2, E1, E2 be set ; for G1 being inducedSubgraph of G,V1,E1
for G2 being inducedSubgraph of G,V2,E2 st V2 c= V1 & E2 c= E1 & V2 is non empty Subset of (the_Vertices_of G) & E2 c= G .edgesBetween V2 holds
G2 is Subgraph of G1
let G1 be inducedSubgraph of G,V1,E1; for G2 being inducedSubgraph of G,V2,E2 st V2 c= V1 & E2 c= E1 & V2 is non empty Subset of (the_Vertices_of G) & E2 c= G .edgesBetween V2 holds
G2 is Subgraph of G1
let G2 be inducedSubgraph of G,V2,E2; ( V2 c= V1 & E2 c= E1 & V2 is non empty Subset of (the_Vertices_of G) & E2 c= G .edgesBetween V2 implies G2 is Subgraph of G1 )
assume that
A1:
( V2 c= V1 & E2 c= E1 )
and
A2:
( V2 is non empty Subset of (the_Vertices_of G) & E2 c= G .edgesBetween V2 )
; G2 is Subgraph of G1
A3:
( the_Vertices_of G2 = V2 & the_Edges_of G2 = E2 )
by A2, Def37;
hence
G2 is Subgraph of G1
; verum