now :: thesis: for A being Am of R ex b2 being non empty Subset of R st
( b2 is Am of R & 1. R in b2 )
let A be Am of R; :: thesis: ex b1 being non empty Subset of R st
( b1 is Am of R & 1. R in b1 )

consider x being Element of A such that
A1: x is_associated_to 1. R by Def7;
set A9 = { z where z is Element of A : z <> x } \/ {(1. R)};
1. R in {(1. R)} by TARSKI:def 1;
then A2: 1. R in { z where z is Element of A : z <> x } \/ {(1. R)} by XBOOLE_0:def 3;
reconsider A9 = { z where z is Element of A : z <> x } \/ {(1. R)} as non empty set ;
A3: for x being Element of A9 holds
( x = 1. R or x in A )
proof
let y be Element of A9; :: thesis: ( y = 1. R or y in A )
per cases ( y in { z where z is Element of A : z <> x } or y in {(1. R)} ) by XBOOLE_0:def 3;
suppose y in { z where z is Element of A : z <> x } ; :: thesis: ( y = 1. R or y in A )
then ex zz being Element of A st
( y = zz & zz <> x ) ;
hence ( y = 1. R or y in A ) ; :: thesis: verum
end;
suppose y in {(1. R)} ; :: thesis: ( y = 1. R or y in A )
hence ( y = 1. R or y in A ) by TARSKI:def 1; :: thesis: verum
end;
end;
end;
now :: thesis: for x being object st x in A9 holds
x in the carrier of R
let x be object ; :: thesis: ( x in A9 implies x in the carrier of R )
now :: thesis: ( x in A9 & x in A9 implies x in the carrier of R )
assume A4: x in A9 ; :: thesis: ( x in A9 implies x in the carrier of R )
x in the carrier of R
proof
now :: thesis: ( ( x = 1. R & x in the carrier of R ) or ( x in A & x in the carrier of R ) )
per cases ( x = 1. R or x in A ) by A3, A4;
case x = 1. R ; :: thesis: x in the carrier of R
hence x in the carrier of R ; :: thesis: verum
end;
case x in A ; :: thesis: x in the carrier of R
hence x in the carrier of R ; :: thesis: verum
end;
end;
end;
hence x in the carrier of R ; :: thesis: verum
end;
hence ( x in A9 implies x in the carrier of R ) ; :: thesis: verum
end;
hence ( x in A9 implies x in the carrier of R ) ; :: thesis: verum
end;
then reconsider A9 = A9 as non empty Subset of R by TARSKI:def 3;
A5: for z, y being Element of A9 st z <> y holds
z is_not_associated_to y
proof
let z, y be Element of A9; :: thesis: ( z <> y implies z is_not_associated_to y )
assume A6: z <> y ; :: thesis: z is_not_associated_to y
now :: thesis: ( ( z = 1. R & y = 1. R & z is_not_associated_to y ) or ( z = 1. R & y <> 1. R & ( z is_associated_to y implies z is_not_associated_to y ) ) or ( z <> 1. R & y = 1. R & ( z is_associated_to y implies z is_not_associated_to y ) ) or ( z <> 1. R & y <> 1. R & z is_not_associated_to y ) )
per cases ( ( z = 1. R & y = 1. R ) or ( z = 1. R & y <> 1. R ) or ( z <> 1. R & y = 1. R ) or ( z <> 1. R & y <> 1. R ) ) ;
end;
end;
hence z is_not_associated_to y ; :: thesis: verum
end;
for a being Element of R ex z being Element of A9 st z is_associated_to a
proof
let a be Element of R; :: thesis: ex z being Element of A9 st z is_associated_to a
now :: thesis: ( ( a is_associated_to 1. R & ex z being Element of A9 st z is_associated_to a ) or ( a is_not_associated_to 1. R & ex z being Element of A9 st z is_associated_to a ) )end;
hence ex z being Element of A9 st z is_associated_to a ; :: thesis: verum
end;
then A9 is Am of R by A5, Def7;
hence ex b1 being non empty Subset of R st
( b1 is Am of R & 1. R in b1 ) by A2; :: thesis: verum
end;
hence ex b1 being non empty Subset of R st
( b1 is Am of R & 1. R in b1 ) ; :: thesis: verum