defpred S1[ object , object ] means $2 = (h . $1) * (g . $1);
A1: for x, y1, y2 being object st x in C & S1[x,y1] & S1[x,y2] holds
y1 = y2 ;
A2: for x, y being object st x in C & S1[x,y] holds
y in REAL by XREAL_0:def 1;
consider IT being PartFunc of C,REAL such that
A3: ( ( for x being object holds
( x in dom IT iff ( x in C & ex y being object st S1[x,y] ) ) ) & ( for x being object st x in dom IT holds
S1[x,IT . x] ) ) from PARTFUN1:sch 2(A2, A1);
for x being object st x in C holds
x in dom IT
proof
let x be object ; :: thesis: ( x in C implies x in dom IT )
A4: ex y being set st y = (h . x) * (g . x) ;
assume x in C ; :: thesis: x in dom IT
hence x in dom IT by A3, A4; :: thesis: verum
end;
then C c= dom IT by TARSKI:def 3;
then A5: dom IT = C by XBOOLE_0:def 10;
then A6: for c being Element of C holds IT . c = (h . c) * (g . c) by A3;
A7: rng g c= [.0,1.] by RELAT_1:def 19;
A8: rng h c= [.0,1.] by RELAT_1:def 19;
for y being object st y in rng IT holds
y in [.0,1.]
proof
reconsider A = [.0,jj.] as non empty closed_interval Subset of REAL by MEASURE5:14;
let y be object ; :: thesis: ( y in rng IT implies y in [.0,1.] )
assume y in rng IT ; :: thesis: y in [.0,1.]
then consider x being Element of C such that
A9: x in dom IT and
A10: y = IT . x by PARTFUN1:3;
A11: A = [.(lower_bound A),(upper_bound A).] by INTEGRA1:4;
then A12: 0 = lower_bound A by INTEGRA1:5;
A13: x in C ;
then x in dom h by FUNCT_2:def 1;
then A14: h . x in rng h by FUNCT_1:def 3;
then A15: 0 <= h . x by A8, A12, INTEGRA2:1;
A16: 1 = upper_bound A by A11, INTEGRA1:5;
x in dom g by A13, FUNCT_2:def 1;
then A17: g . x in rng g by FUNCT_1:def 3;
then A18: g . x <= 1 by A7, A16, INTEGRA2:1;
0 <= g . x by A7, A12, A17, INTEGRA2:1;
then 0 <= (h . x) * (g . x) by A15, XREAL_1:127;
then A19: 0 <= IT . x by A3, A9;
h . x <= 1 by A8, A16, A14, INTEGRA2:1;
then (h . x) * (g . x) <= 1 by A15, A18, XREAL_1:160;
then IT . x <= 1 by A3, A9;
hence y in [.0,1.] by A10, A12, A16, A19, INTEGRA2:1; :: thesis: verum
end;
then rng IT c= [.0,1.] by TARSKI:def 3;
then IT is Membership_Func of C by A5, FUNCT_2:def 1, RELAT_1:def 19;
hence ex b1 being Membership_Func of C st
for c being Element of C holds b1 . c = (h . c) * (g . c) by A6; :: thesis: verum