set I = I_{1} ;
a2:
for x being Element of [.0,1.] holds I_{1} . (x,x) = 1
SS:
1 in [.0,1.]
by XXREAL_1:1;
not for y being Element of [.0,1.] holds I_{1} . (1,y) = y
then A3:
not I_{1} is satisfying_(NP)
;
for x, y, z being Element of [.0,1.] holds I_{1} . (x,(I_{1} . (y,z))) = I_{1} . (y,(I_{1} . (x,z)))
proof
let x,
y,
z be
Element of
[.0,1.];
I_{1} . (x,(I_{1} . (y,z))) = I_{1} . (y,(I_{1} . (x,z)))
(
y <= 1 &
x <= 1 &
z >= 0 )
by XXREAL_1:1;
per cases then
( ( z = 0 & x = 1 & y = 1 ) or ( z > 0 & x = 1 & y = 1 ) or ( z = 0 & x = 1 & y < 1 ) or ( z = 0 & x < 1 & y = 1 ) or ( z = 0 & x < 1 & y < 1 ) or ( z > 0 & x < 1 & y = 1 ) or ( z > 0 & x = 1 & y < 1 ) or ( z > 0 & x < 1 & y < 1 ) )
by XXREAL_0:1;
suppose B1:
(
z = 0 &
x = 1 &
y = 1 )
;
I_{1} . (x,(I_{1} . (y,z))) = I_{1} . (y,(I_{1} . (x,z)))then B2:
I_{1} . (
x,
(I_{1} . (y,z))) =
I_{1} . (
x,
0)
by FUZIMPL1:def 25
.=
0
by B1, FUZIMPL1:def 25
;
I_{1} . (
y,
(I_{1} . (x,z))) =
I_{1} . (
y,
0)
by FUZIMPL1:def 25, B1
.=
0
by B1, FUZIMPL1:def 25
;
hence
I_{1} . (
x,
(I_{1} . (y,z)))
= I_{1} . (
y,
(I_{1} . (x,z)))
by B2;
verum end; suppose B1:
(
z > 0 &
x = 1 &
y = 1 )
;
I_{1} . (x,(I_{1} . (y,z))) = I_{1} . (y,(I_{1} . (x,z)))then B2:
I_{1} . (
x,
(I_{1} . (y,z))) =
I_{1} . (
x,1)
by FUZIMPL1:def 25
.=
1
by FUZIMPL1:def 25, SS
;
I_{1} . (
y,
(I_{1} . (x,z))) =
I_{1} . (
y,1)
by FUZIMPL1:def 25, B1
.=
1
by FUZIMPL1:def 25, SS
;
hence
I_{1} . (
x,
(I_{1} . (y,z)))
= I_{1} . (
y,
(I_{1} . (x,z)))
by B2;
verum end; end;
end;
then
I_{1} is satisfying_(EP)
;
hence
( not I_{1} is satisfying_(NP) & I_{1} is satisfying_(EP) & I_{1} is satisfying_(IP) & not I_{1} is satisfying_(OP) )
by a2, A3; verum