let X, Y be set ; for f being Function of X,Y holds
( f is onto iff [:f,f:] is onto )
let f be Function of X,Y; ( f is onto iff [:f,f:] is onto )
rng [:f,f:] = [:(rng f),(rng f):]
by FUNCT_3:67;
then
( rng f = Y iff rng [:f,f:] = [:Y,Y:] )
by ZFMISC_1:92;
hence
( f is onto iff [:f,f:] is onto )
; verum