let i be non zero Integer; :: thesis: |.sin.| + |.cos.| is (PI / 2) * i -periodic
i in INT by INT_1:def 2;
then consider k being Nat such that
A1: ( i = k or i = - k ) by INT_1:def 1;
per cases ( i = k or i = - k ) by A1;
suppose i = k ; :: thesis: |.sin.| + |.cos.| is (PI / 2) * i -periodic
end;
suppose A2: i = - k ; :: thesis: |.sin.| + |.cos.| is (PI / 2) * i -periodic
then consider m being Nat such that
A3: - i = m + 1 by NAT_1:6;
|.sin.| + |.cos.| is (PI / 2) * (m + 1) -periodic by Lm19;
then |.sin.| + |.cos.| is - ((PI / 2) * (m + 1)) -periodic by Th14;
hence |.sin.| + |.cos.| is (PI / 2) * i -periodic by A2, A3; :: thesis: verum
end;
end;