let z be object ; for f being Function
for x, y being object st x <> y holds
(f +~ (x,y)) +~ (x,z) = f +~ (x,y)
let f be Function; for x, y being object st x <> y holds
(f +~ (x,y)) +~ (x,z) = f +~ (x,y)
let x, y be object ; ( x <> y implies (f +~ (x,y)) +~ (x,z) = f +~ (x,y) )
assume
x <> y
; (f +~ (x,y)) +~ (x,z) = f +~ (x,y)
then
not x in rng (f +~ (x,y))
by Th100;
hence
(f +~ (x,y)) +~ (x,z) = f +~ (x,y)
by Th103; verum