let x be set ; for f, g being Function st x in (dom f) /\ (dom g) holds
<:f,g:> . x = [(f . x),(g . x)]
let f, g be Function; ( x in (dom f) /\ (dom g) implies <:f,g:> . x = [(f . x),(g . x)] )
assume
x in (dom f) /\ (dom g)
; <:f,g:> . x = [(f . x),(g . x)]
then
x in dom <:f,g:>
by Def7;
hence
<:f,g:> . x = [(f . x),(g . x)]
by Def7; verum