reconsider B = REAL \ NAT as Subset of R^1 by TOPMETR:17;
let A be Subset of REAL?; :: thesis: ( A = {REAL} implies A is closed )
reconsider B = B as Subset of R^1 ;
A1: REAL \ NAT = ((REAL \ NAT) \/ {REAL}) \ {REAL}
proof end;
B misses NAT by XBOOLE_1:79;
then A6: B /\ NAT = {} ;
then reconsider C = B as Subset of REAL? by Th29;
assume A = {REAL} ; :: thesis: A is closed
then A7: C = A ` by A1, Def8;
B is open
proof
reconsider N = NAT as Subset of R^1 by TOPMETR:17, NUMBERS:19;
reconsider N = N as Subset of R^1 ;
( N is closed & N ` = B ) by Th10, TOPMETR:17;
hence B is open by TOPS_1:3; :: thesis: verum
end;
then C is open by A6, Th30;
hence A is closed by A7, TOPS_1:3; :: thesis: verum