let U be non empty set ; for S1, S2 being Language st TheEqSymbOf S1 = TheEqSymbOf S2 & TheNorSymbOf S1 = TheNorSymbOf S2 holds
for I1 being Element of U -InterpretersOf S1
for I2 being Element of U -InterpretersOf S2
for phi1 being wff string of S1 st the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) holds
ex phi2 being wff string of S2 st phi1 = phi2
let S1, S2 be Language; ( TheEqSymbOf S1 = TheEqSymbOf S2 & TheNorSymbOf S1 = TheNorSymbOf S2 implies for I1 being Element of U -InterpretersOf S1
for I2 being Element of U -InterpretersOf S2
for phi1 being wff string of S1 st the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) holds
ex phi2 being wff string of S2 st phi1 = phi2 )
set O1 = OwnSymbolsOf S1;
set O2 = OwnSymbolsOf S2;
set a1 = the adicity of S1;
set a2 = the adicity of S2;
set E1 = TheEqSymbOf S1;
set E2 = TheEqSymbOf S2;
set F1 = S1 -firstChar ;
set F2 = S2 -firstChar ;
set AS1 = AtomicFormulaSymbolsOf S1;
set AS2 = AtomicFormulaSymbolsOf S2;
set N1 = TheNorSymbOf S1;
set N2 = TheNorSymbOf S2;
set II1 = U -InterpretersOf S1;
set II2 = U -InterpretersOf S2;
assume A1:
( TheEqSymbOf S1 = TheEqSymbOf S2 & TheNorSymbOf S1 = TheNorSymbOf S2 )
; for I1 being Element of U -InterpretersOf S1
for I2 being Element of U -InterpretersOf S2
for phi1 being wff string of S1 st the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) holds
ex phi2 being wff string of S2 st phi1 = phi2
defpred S1[ Nat] means for I1 being Element of U -InterpretersOf S1
for I2 being Element of U -InterpretersOf S2
for phi1 being $1 -wff string of S1 st the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) holds
ex phi2 being $1 -wff string of S2 st phi1 = phi2;
A2:
S1[ 0 ]
A4:
for n being Nat st S1[n] holds
S1[n + 1]
proof
let n be
Nat;
( S1[n] implies S1[n + 1] )
set N =
n + 1;
assume A5:
S1[
n]
;
S1[n + 1]
let I1 be
Element of
U -InterpretersOf S1;
for I2 being Element of U -InterpretersOf S2
for phi1 being n + 1 -wff string of S1 st the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) holds
ex phi2 being n + 1 -wff string of S2 st phi1 = phi2let I2 be
Element of
U -InterpretersOf S2;
for phi1 being n + 1 -wff string of S1 st the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) holds
ex phi2 being n + 1 -wff string of S2 st phi1 = phi2let phi1 be
n + 1
-wff string of
S1;
( the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) implies ex phi2 being n + 1 -wff string of S2 st phi1 = phi2 )
set x1 =
rng phi1;
set x11 =
(rng phi1) /\ (OwnSymbolsOf S1);
assume A6:
( the
adicity of
S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the
adicity of
S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) &
I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) )
;
ex phi2 being n + 1 -wff string of S2 st phi1 = phi2
per cases
( phi1 is 0wff or not phi1 is 0wff )
;
suppose
not
phi1 is
0wff
;
ex phi2 being n + 1 -wff string of S2 st phi1 = phi2then reconsider phi11 =
phi1 as non
0wff n + 1
-wff string of
S1 ;
reconsider h1 =
head phi11 as
n -wff string of
S1 ;
set t11 =
tail phi11;
set l11 =
(S1 -firstChar) . phi11;
A8:
phi11 = (<*((S1 -firstChar) . phi11)*> ^ h1) ^ (tail phi11)
by FOMODEL2:23;
then
(
rng h1 c= rng (<*((S1 -firstChar) . phi11)*> ^ h1) &
rng (<*((S1 -firstChar) . phi11)*> ^ h1) c= rng phi1 )
by FINSEQ_1:30, FINSEQ_1:29;
then reconsider y1 =
rng h1 as non
empty Subset of
(rng phi1) by XBOOLE_1:1;
reconsider y11 =
y1 /\ (OwnSymbolsOf S1) as
Subset of
((rng phi1) /\ (OwnSymbolsOf S1)) by XBOOLE_1:26;
A9:
I1 | (y11 null ((rng phi1) /\ (OwnSymbolsOf S1))) =
(I1 | ((rng phi1) /\ (OwnSymbolsOf S1))) | y11
by RELAT_1:71
.=
I2 | (y11 null ((rng phi1) /\ (OwnSymbolsOf S1)))
by RELAT_1:71, A6
;
the
adicity of
S1 | (y11 null ((rng phi1) /\ (OwnSymbolsOf S1))) =
( the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1))) | y11
by RELAT_1:71
.=
the
adicity of
S2 | (y11 null ((rng phi1) /\ (OwnSymbolsOf S1)))
by RELAT_1:71, A6
;
then consider h2 being
n -wff string of
S2 such that A10:
h1 = h2
by A5, A9;
per cases
( phi11 is exal or not phi11 is exal )
;
suppose
phi11 is
exal
;
ex phi2 being n + 1 -wff string of S2 st phi1 = phi2then reconsider phi11 =
phi11 as non
0wff n + 1
-wff exal string of
S1 ;
reconsider l1 =
(S1 -firstChar) . phi11 as
literal Element of
S1 ;
phi1 null {} is
(rng phi1) \/ {} -valued
;
then
{(phi1 . 1)} \ (rng phi1) = {}
;
then
phi1 . 1
in rng phi1
by ZFMISC_1:60;
then
(
l1 in rng phi1 &
l1 in OwnSymbolsOf S1 &
dom the
adicity of
S1 = AtomicFormulaSymbolsOf S1 )
by FOMODEL0:6, FOMODEL1:def 19, FUNCT_2:def 1;
then A11:
(
l1 in (rng phi1) /\ (OwnSymbolsOf S1) &
dom ( the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1))) = (AtomicFormulaSymbolsOf S1) /\ ((rng phi1) /\ (OwnSymbolsOf S1)) &
l1 in AtomicFormulaSymbolsOf S1 )
by RELAT_1:61, XBOOLE_0:def 4, FOMODEL1:def 20;
then
(
l1 in dom ( the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1))) &
dom ( the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1))) = ((rng phi1) /\ (OwnSymbolsOf S1)) /\ (dom the adicity of S2) )
by XBOOLE_0:def 4, RELAT_1:61, A6;
then
(
l1 in dom the
adicity of
S2 &
dom the
adicity of
S2 = AtomicFormulaSymbolsOf S2 )
by FUNCT_2:def 1;
then reconsider l2 =
l1 as
ofAtomicFormula Element of
S2 by FOMODEL1:def 20;
l2 in OwnSymbolsOf S2
by A1, FOMODEL1:15;
then reconsider l2 =
l2 as
own Element of
S2 ;
ar l1 =
( the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1))) . l1
by A11, FUNCT_1:49
.=
ar l2
by A6, A11, FUNCT_1:49
;
then
not
l2 is
low-compounding
;
then reconsider l2 =
l2 as
literal Element of
S2 ;
take phi2 =
<*l2*> ^ h2;
phi1 = phi2
phi11 = (<*l2*> ^ h1) ^ (tail phi11)
by FOMODEL2:23;
hence
phi1 = phi2
by A10;
verumreconsider l2 =
l2 as
literal Element of
S2 ;
end; end; end; end;
end;
A14:
for n being Nat holds S1[n]
from NAT_1:sch 2(A2, A4);
let I1 be Element of U -InterpretersOf S1; for I2 being Element of U -InterpretersOf S2
for phi1 being wff string of S1 st the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) holds
ex phi2 being wff string of S2 st phi1 = phi2
let I2 be Element of U -InterpretersOf S2; for phi1 being wff string of S1 st the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) holds
ex phi2 being wff string of S2 st phi1 = phi2
let phi1 be wff string of S1; ( the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) implies ex phi2 being wff string of S2 st phi1 = phi2 )
set d = Depth phi1;
phi1 null 0 is (Depth phi1) + 0 -wff
;
then reconsider phi11 = phi1 as Depth phi1 -wff string of S1 ;
set x1 = rng phi1;
set x11 = (rng phi1) /\ (OwnSymbolsOf S1);
assume
( the adicity of S1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = the adicity of S2 | ((rng phi1) /\ (OwnSymbolsOf S1)) & I1 | ((rng phi1) /\ (OwnSymbolsOf S1)) = I2 | ((rng phi1) /\ (OwnSymbolsOf S1)) )
; ex phi2 being wff string of S2 st phi1 = phi2
then consider phi2 being Depth phi1 -wff string of S2 such that
A15:
phi2 = phi11
by A14;
take
phi2
; phi1 = phi2
thus
phi1 = phi2
by A15; verum