let FT be non empty RelStr ; for g being FinSequence of FT
for k being Element of NAT st g is continuous & k < len g holds
g /^ k is continuous
let g be FinSequence of FT; for k being Element of NAT st g is continuous & k < len g holds
g /^ k is continuous
let k be Element of NAT ; ( g is continuous & k < len g implies g /^ k is continuous )
assume that
A1:
g is continuous
and
A2:
k < len g
; g /^ k is continuous
A3:
(len g) - k > 0
by A2, XREAL_1:50;
then A4:
(len g) - k = (len g) -' k
by XREAL_0:def 2;
A5:
len (g /^ k) = (len g) - k
by A2, RFINSEQ:def 1;
A6:
for i being Nat
for x11 being Element of FT st 1 <= i & i < len (g /^ k) & x11 = (g /^ k) . i holds
(g /^ k) . (i + 1) in U_FT x11
proof
let i be
Nat;
for x11 being Element of FT st 1 <= i & i < len (g /^ k) & x11 = (g /^ k) . i holds
(g /^ k) . (i + 1) in U_FT x11let x11 be
Element of
FT;
( 1 <= i & i < len (g /^ k) & x11 = (g /^ k) . i implies (g /^ k) . (i + 1) in U_FT x11 )
assume that A7:
1
<= i
and A8:
i < len (g /^ k)
and A9:
x11 = (g /^ k) . i
;
(g /^ k) . (i + 1) in U_FT x11
A10:
1
<= 1
+ i
by NAT_1:11;
i in dom (g /^ k)
by A7, A8, FINSEQ_3:25;
then A11:
(g /^ k) . i = g . (i + k)
by A2, RFINSEQ:def 1;
i <= i + k
by NAT_1:11;
then A12:
(
(i + 1) + k = (i + k) + 1 & 1
<= i + k )
by A7, XXREAL_0:2;
i + 1
<= (len g) -' k
by A5, A4, A8, NAT_1:13;
then
i + 1
in dom (g /^ k)
by A5, A4, A10, FINSEQ_3:25;
then A13:
(g /^ k) . (i + 1) = g . ((i + 1) + k)
by A2, RFINSEQ:def 1;
i + k < ((len g) - k) + k
by A5, A8, XREAL_1:6;
hence
(g /^ k) . (i + 1) in U_FT x11
by A1, A9, A11, A13, A12;
verum
end;
(len g) -' k >= 0 + 1
by A3, A4, NAT_1:13;
hence
g /^ k is continuous
by A5, A4, A6; verum