let FT be non empty RelStr ; for f being FinSequence of FT
for x, y being Element of FT st f is continuous & y = f . (len f) & x in U_FT y holds
f ^ <*x*> is continuous
let f be FinSequence of FT; for x, y being Element of FT st f is continuous & y = f . (len f) & x in U_FT y holds
f ^ <*x*> is continuous
let x, y be Element of FT; ( f is continuous & y = f . (len f) & x in U_FT y implies f ^ <*x*> is continuous )
assume that
A1:
f is continuous
and
A2:
y = f . (len f)
and
A3:
x in U_FT y
; f ^ <*x*> is continuous
reconsider g = f ^ <*x*> as FinSequence of FT ;
A4:
dom f = Seg (len f)
by FINSEQ_1:def 3;
A5:
len <*x*> = 1
by FINSEQ_1:39;
A6:
for i being Nat
for x1 being Element of FT st 1 <= i & i < len g & x1 = g . i holds
g . (i + 1) in U_FT x1
proof
let i be
Nat;
for x1 being Element of FT st 1 <= i & i < len g & x1 = g . i holds
g . (i + 1) in U_FT x1let x1 be
Element of
FT;
( 1 <= i & i < len g & x1 = g . i implies g . (i + 1) in U_FT x1 )
assume that A7:
1
<= i
and A8:
i < len g
and A9:
x1 = g . i
;
g . (i + 1) in U_FT x1
(
i + 1
<= len g & 1
< i + 1 )
by A7, A8, NAT_1:13;
then
i + 1
in dom g
by FINSEQ_3:25;
then
g . (i + 1) = g /. (i + 1)
by PARTFUN1:def 6;
then reconsider x2 =
g . (i + 1) as
Element of
FT ;
now x2 in U_FT x1per cases
( i < len f or i >= len f )
;
suppose A13:
i >= len f
;
x2 in U_FT x1
len g = (len f) + 1
by A5, FINSEQ_1:22;
then A14:
i <= len f
by A8, NAT_1:13;
then A15:
i = len f
by A13, XXREAL_0:1;
i in dom f
by A4, A7, A14;
then
x1 = y
by A2, A9, A15, FINSEQ_1:def 7;
hence
x2 in U_FT x1
by A3, A15, FINSEQ_1:42;
verum end; end; end;
hence
g . (i + 1) in U_FT x1
;
verum
end;
len (f ^ <*x*>) =
(len f) + (len <*x*>)
by FINSEQ_1:22
.=
(len f) + 1
by FINSEQ_1:39
;
then
len (f ^ <*x*>) >= 1
by NAT_1:11;
hence
f ^ <*x*> is continuous
by A6; verum