let D be non empty set ; for d being Element of D
for F being BinOp of D st F is associative & F is having_a_unity & F is having_an_inverseOp holds
(F * ((id D),(the_inverseOp_wrt F))) . (d,(the_unity_wrt F)) = d
let d be Element of D; for F being BinOp of D st F is associative & F is having_a_unity & F is having_an_inverseOp holds
(F * ((id D),(the_inverseOp_wrt F))) . (d,(the_unity_wrt F)) = d
let F be BinOp of D; ( F is associative & F is having_a_unity & F is having_an_inverseOp implies (F * ((id D),(the_inverseOp_wrt F))) . (d,(the_unity_wrt F)) = d )
assume that
A1:
F is associative
and
A2:
F is having_a_unity
and
A3:
F is having_an_inverseOp
; (F * ((id D),(the_inverseOp_wrt F))) . (d,(the_unity_wrt F)) = d
set u = the_inverseOp_wrt F;
set e = the_unity_wrt F;
thus (F * ((id D),(the_inverseOp_wrt F))) . (d,(the_unity_wrt F)) =
F . (d,((the_inverseOp_wrt F) . (the_unity_wrt F)))
by Th81
.=
F . (d,(the_unity_wrt F))
by A1, A2, A3, Th61
.=
d
by A2, SETWISEO:15
; verum