let D be non empty set ; for p1, p2, p3 being Element of D holds <*p1,p2,p3*> /^ 1 = <*p2,p3*>
let p1, p2, p3 be Element of D; <*p1,p2,p3*> /^ 1 = <*p2,p3*>
<*p1,p2,p3*> = <*p1*> ^ <*p2,p3*>
by FINSEQ_1:43;
hence
<*p1,p2,p3*> /^ 1 = <*p2,p3*>
by Th45; verum