set p = <%(1. (Z/ 2)),(1. (Z/ 2)),(1. (Z/ 2))%>;
set a = the Element of Roots <%(1. (Z/ 2)),(1. (Z/ 2)),(1. (Z/ 2))%>;
now not Roots <%(1. (Z/ 2)),(1. (Z/ 2)),(1. (Z/ 2))%> <> {} assume A:
Roots <%(1. (Z/ 2)),(1. (Z/ 2)),(1. (Z/ 2))%> <> {}
;
contradictionthen
the
Element of
Roots <%(1. (Z/ 2)),(1. (Z/ 2)),(1. (Z/ 2))%> in Roots <%(1. (Z/ 2)),(1. (Z/ 2)),(1. (Z/ 2))%>
;
then reconsider a = the
Element of
Roots <%(1. (Z/ 2)),(1. (Z/ 2)),(1. (Z/ 2))%> as
Element of
(Z/ 2) ;
B:
a is_a_root_of <%(1. (Z/ 2)),(1. (Z/ 2)),(1. (Z/ 2))%>
by A, POLYNOM5:def 10;
end;
hence
Roots X^2+X+1 = {}
; verum