let F be non 2 -characteristic polynomial_disjoint non quadratic_complete Field; for p being quadratic non DC-square Element of the carrier of (Polynom-Ring F) holds FAdj (F,{(sqrt (DC p))}) is SplittingField of p
let p be quadratic non DC-square Element of the carrier of (Polynom-Ring F); FAdj (F,{(sqrt (DC p))}) is SplittingField of p
set E = FAdj (F,{(sqrt (DC p))});
set r1 = Root1 p;
set r2 = Root2 p;
reconsider q = (rpoly (1,(Root1 p))) *' (rpoly (1,(Root2 p))) as Element of the carrier of (Polynom-Ring (FAdj (F,{(sqrt (DC p))}))) by POLYNOM3:def 10;
K:
F is Subring of FAdj (F,{(sqrt (DC p))})
by FIELD_4:def 1;
(rpoly (1,(Root1 p))) *' (rpoly (1,(Root2 p))) = (X- (Root1 p)) *' (X- (Root2 p))
;
then D:
p = (@ ((LC p),(FAdj (F,{(sqrt (DC p))})))) * ((rpoly (1,(Root1 p))) *' (rpoly (1,(Root2 p))))
by Z5;
( rpoly (1,(Root1 p)) is Ppoly of FAdj (F,{(sqrt (DC p))}) & rpoly (1,(Root2 p)) is Ppoly of FAdj (F,{(sqrt (DC p))}) )
by RING_5:51;
then
(rpoly (1,(Root1 p))) *' (rpoly (1,(Root2 p))) is Ppoly of FAdj (F,{(sqrt (DC p))})
by RING_5:52;
then A:
p splits_in FAdj (F,{(sqrt (DC p))})
by Y, D, FIELD_4:def 5;
now for U being FieldExtension of F st p splits_in U & U is Subfield of FAdj (F,{(sqrt (DC p))}) holds
U == FAdj (F,{(sqrt (DC p))})let U be
FieldExtension of
F;
( p splits_in U & U is Subfield of FAdj (F,{(sqrt (DC p))}) implies U == FAdj (F,{(sqrt (DC p))}) )assume D0:
(
p splits_in U &
U is
Subfield of
FAdj (
F,
{(sqrt (DC p))}) )
;
U == FAdj (F,{(sqrt (DC p))})then D3:
(
FAdj (
F,
{(sqrt (DC p))}) is
U -extending &
U is
Subring of
FAdj (
F,
{(sqrt (DC p))}) )
by FIELD_5:12, FIELD_4:7;
D4:
Roots (
(FAdj (F,{(sqrt (DC p))})),
p)
c= the
carrier of
U
by D3, D0, A, FIELD_8:27;
Roots (
(FAdj (F,{(sqrt (DC p))})),
p)
= {(Root1 p),(Root2 p)}
by Z4;
then
Root1 p in Roots (
(FAdj (F,{(sqrt (DC p))})),
p)
by TARSKI:def 2;
then reconsider w =
Root1 p as
Element of
U by D4;
sqrt (DC p) in the
carrier of
U
proof
consider aF being non
zero Element of
F,
bF,
cF being
Element of
F such that A1:
p = <%cF,bF,aF%>
by qua5;
set aE =
@ (
aF,
(FAdj (F,{(sqrt (DC p))})));
set bE =
@ (
bF,
(FAdj (F,{(sqrt (DC p))})));
set cE =
@ (
cF,
(FAdj (F,{(sqrt (DC p))})));
not
FAdj (
F,
{(sqrt (DC p))}) is 2
-characteristic
by K;
then C3:
2
'*' (@ (aF,(FAdj (F,{(sqrt (DC p))})))) <> 0. (FAdj (F,{(sqrt (DC p))}))
by C1, ch2;
I1:
(
@ (
aF,
(FAdj (F,{(sqrt (DC p))})))
= aF &
@ (
bF,
(FAdj (F,{(sqrt (DC p))})))
= bF &
@ (
cF,
(FAdj (F,{(sqrt (DC p))})))
= cF )
by FIELD_7:def 4;
then
p = <%(@ (cF,(FAdj (F,{(sqrt (DC p))})))),(@ (bF,(FAdj (F,{(sqrt (DC p))})))),(@ (aF,(FAdj (F,{(sqrt (DC p))}))))%>
by A1, eval2;
then
Root1 p = ((- (@ (bF,(FAdj (F,{(sqrt (DC p))}))))) + (RootDC p)) * ((2 '*' (@ (aF,(FAdj (F,{(sqrt (DC p))}))))) ")
by C1, Z2;
then (Root1 p) * (2 '*' (@ (aF,(FAdj (F,{(sqrt (DC p))}))))) =
((- (@ (bF,(FAdj (F,{(sqrt (DC p))}))))) + (RootDC p)) * (((2 '*' (@ (aF,(FAdj (F,{(sqrt (DC p))}))))) ") * (2 '*' (@ (aF,(FAdj (F,{(sqrt (DC p))}))))))
by GROUP_1:def 3
.=
((- (@ (bF,(FAdj (F,{(sqrt (DC p))}))))) + (RootDC p)) * (1. (FAdj (F,{(sqrt (DC p))})))
by C3, VECTSP_1:def 10
;
then B:
(@ (bF,(FAdj (F,{(sqrt (DC p))})))) + ((Root1 p) * (2 '*' (@ (aF,(FAdj (F,{(sqrt (DC p))})))))) =
((@ (bF,(FAdj (F,{(sqrt (DC p))})))) + (- (@ (bF,(FAdj (F,{(sqrt (DC p))})))))) + (RootDC p)
by RLVECT_1:def 3
.=
(0. (FAdj (F,{(sqrt (DC p))}))) + (RootDC p)
by RLVECT_1:5
;
set aU =
@ (
aF,
U);
set bU =
@ (
bF,
U);
set cU =
@ (
cF,
U);
I2:
(
@ (
aF,
U)
= aF &
@ (
bF,
U)
= bF &
@ (
cF,
U)
= cF )
by FIELD_7:def 4;
2
'*' (@ (aF,U)) = 2
'*' (@ (aF,(FAdj (F,{(sqrt (DC p))}))))
by D3, I2, Z3, FIELD_7:def 4;
then
w * (2 '*' (@ (aF,U))) = (Root1 p) * (2 '*' (@ (aF,(FAdj (F,{(sqrt (DC p))})))))
by D3, FIELD_6:16;
then
(@ (bF,U)) + (w * (2 '*' (@ (aF,U)))) = (@ (bF,(FAdj (F,{(sqrt (DC p))})))) + ((Root1 p) * (2 '*' (@ (aF,(FAdj (F,{(sqrt (DC p))}))))))
by D3, I1, I2, FIELD_6:15;
hence
sqrt (DC p) in the
carrier of
U
by B;
verum
end; then D1:
{(sqrt (DC p))} c= the
carrier of
U
by TARSKI:def 1;
D2:
U is
Subfield of
embField (canHomP (X^2- (DC p)))
by D0, EC_PF_1:5;
F is
Subfield of
U
by FIELD_4:7;
then
FAdj (
F,
{(sqrt (DC p))}) is
Subfield of
U
by D1, D2, FIELD_6:37;
hence
U == FAdj (
F,
{(sqrt (DC p))})
by D0, FIELD_7:def 2;
verum end;
hence
FAdj (F,{(sqrt (DC p))}) is SplittingField of p
by A, FIELD_8:def 1; verum