let F be non 2 -characteristic polynomial_disjoint non quadratic_complete Field; for a being non square Element of F holds the carrier of (FAdj (F,{(sqrt a)})) = { (y + ((@ (sqrt a)) * z)) where y, z is F -membered Element of (FAdj (F,{(sqrt a)})) : verum }
let a be non square Element of F; the carrier of (FAdj (F,{(sqrt a)})) = { (y + ((@ (sqrt a)) * z)) where y, z is F -membered Element of (FAdj (F,{(sqrt a)})) : verum }
A:
now for o being object st o in the carrier of (FAdj (F,{(sqrt a)})) holds
o in { (y + ((@ (sqrt a)) * z)) where y, z is F -membered Element of (FAdj (F,{(sqrt a)})) : verum } let o be
object ;
( o in the carrier of (FAdj (F,{(sqrt a)})) implies o in { (y + ((@ (sqrt a)) * z)) where y, z is F -membered Element of (FAdj (F,{(sqrt a)})) : verum } )assume
o in the
carrier of
(FAdj (F,{(sqrt a)}))
;
o in { (y + ((@ (sqrt a)) * z)) where y, z is F -membered Element of (FAdj (F,{(sqrt a)})) : verum } then
ex
y,
z being
F -membered Element of
(FAdj (F,{(sqrt a)})) st
o = y + ((@ (sqrt a)) * z)
by qbase2;
hence
o in { (y + ((@ (sqrt a)) * z)) where y, z is F -membered Element of (FAdj (F,{(sqrt a)})) : verum }
;
verum end;
hence
the carrier of (FAdj (F,{(sqrt a)})) = { (y + ((@ (sqrt a)) * z)) where y, z is F -membered Element of (FAdj (F,{(sqrt a)})) : verum }
by A, TARSKI:2; verum