let F be non 2 -characteristic polynomial_disjoint non quadratic_complete Field; for a being non square Element of F holds {(1. F),(sqrt a)} is Basis of (VecSp ((FAdj (F,{(sqrt a)})),F))
let a be non square Element of F; {(1. F),(sqrt a)} is Basis of (VecSp ((FAdj (F,{(sqrt a)})),F))
Base (sqrt a) = {(1. F),(sqrt a)}
by qbase1;
hence
{(1. F),(sqrt a)} is Basis of (VecSp ((FAdj (F,{(sqrt a)})),F))
by FIELD_6:65; verum