set FX = Polynom-Ring F;
set I = {p} -Ideal ;
set K = (Polynom-Ring F) / ({p} -Ideal);
set x = the Element of ([#] ((Polynom-Ring F) / ({p} -Ideal))) /\ ([#] (Polynom-Ring ((Polynom-Ring F) / ({p} -Ideal))));
now (Polynom-Ring F) / ({p} -Ideal) is polynomial_disjoint assume A1:
not
(Polynom-Ring F) / ({p} -Ideal) is
polynomial_disjoint
;
contradictionthen A2:
( the
Element of
([#] ((Polynom-Ring F) / ({p} -Ideal))) /\ ([#] (Polynom-Ring ((Polynom-Ring F) / ({p} -Ideal)))) in [#] ((Polynom-Ring F) / ({p} -Ideal)) & the
Element of
([#] ((Polynom-Ring F) / ({p} -Ideal))) /\ ([#] (Polynom-Ring ((Polynom-Ring F) / ({p} -Ideal)))) in [#] (Polynom-Ring ((Polynom-Ring F) / ({p} -Ideal))) )
by XBOOLE_0:def 4;
reconsider x = the
Element of
([#] ((Polynom-Ring F) / ({p} -Ideal))) /\ ([#] (Polynom-Ring ((Polynom-Ring F) / ({p} -Ideal)))) as
Element of
((Polynom-Ring F) / ({p} -Ideal)) by A1, XBOOLE_0:def 4;
reconsider q =
x as
Polynomial of
((Polynom-Ring F) / ({p} -Ideal)) by A2, POLYNOM3:def 10;
consider a being
Element of
(Polynom-Ring F) such that A3:
x = Class (
(EqRel ((Polynom-Ring F),({p} -Ideal))),
a)
by RING_1:11;
reconsider p =
a as
Polynomial of
F by POLYNOM3:def 10;
for
o being
object st
o in q holds
ex
n being
Element of
NAT ex
u being
object st
o = [n,u]
then consider n being
Element of
NAT ,
u being
object such that A5:
p = [n,u]
by A3, EQREL_1:20;
dom p = NAT
by FUNCT_2:def 1;
then
[n,(p . n)] in p
by FUNCT_1:1;
then A6:
[n,(p . n)] in {{n},{n,u}}
by A5, TARSKI:def 5;
now for a, b being object holds not [n,a] in {{n},{n,b}}let a,
b be
object ;
not [n,a] in {{n},{n,b}}assume
[n,a] in {{n},{n,b}}
;
contradictionthen A7:
{{n},{n,a}} in {{n},{n,b}}
by TARSKI:def 5;
end; hence
contradiction
by A6;
verum end;
hence
(Polynom-Ring F) / ({p} -Ideal) is polynomial_disjoint
; verum